Answer:r=3cm,diameter =6cm and C=18.84cm
Step-by-step explanation:
To find the radius,diameter and circumference according to the diagram drawn above
r=3cm
Diameter=2×3cm
d=6cm
To find the circumference
C=2πr
C=2×3.14×3cm
C=18.84cm
Answer:
7t^2 + 21t
Step-by-step explanation:
You have 7 tiles of each t by t+3.
One tile has an area of
t * (t+3) = t^2 + 3t
So in total the area is
7* (t^2 + 3t)
7t^2 + 21t
1)7; divide by 7 2)-3; divide by 2 3)8; divide by -4 4)54; multiply by 6 5)80; multiply by -10 6)-6; divide by -9 7)-5; divide by -12 8)-40; multiply by 20 9)-90; multiply by 10 10)20 11)615; plug in 205 for R and 3 in T. multiply by 3
Answer:
x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z
Step-by-step explanation:
Solve for x:
2 sqrt(2) = 4^x
Hint: | Reverse the equality in 2 sqrt(2) = 4^x in order to isolate x to the left hand side.
2 sqrt(2) = 4^x is equivalent to 4^x = 2 sqrt(2):
4^x = 2 sqrt(2)
Hint: | Eliminate the exponential from the left hand side.
Take the logarithm base 4 of both sides:
Answer:x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z
Answer:
Answer (B) and (D)
Step-by-step explanation:
First we need to figure out: What is quadrant II about?
As said in the picture provided, quadrant II is in the upper left corner of a graph.
For a point to be in QII, the <em>x values need to be negative</em>, and <em>the y values need to be positive</em>.
B: (-4,2) and D: (-3,5) would belong in QII.
<em>Their x values are negative, and the y values are positive. </em>
<em>Therefore, </em><em>B and D would be the correct answers.</em>
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