Answer:
Step-by-step explanation:
we have
we know that
In this problem
substitute in the formula
Answer:
2 feet
Step-by-step explanation:
The shoreline is eroding at 1/3 foot per 2 months. There are 12 months in a year so you multiply 1/3 x 6 and you get 2.
Answer:
It should be "one solution"
Step-by-step explanation:
After graphing the equations, the two lines only intersect at one point which makes it "one solution." Hope this helps.
To start off, you can divide the right side of the equation by x to get rid of most of the x's so you get the polynomial x^4 - 10x^2 + 9. This means that f(x) = x^4 - 10x^2 + 9x. By factoring the right side of the equation, you get f(x) = (x^2 - 1)(x^2 - 9). I think the minimum value is 1 and the maximum value is 3.
Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
