If an atom is neutral, what two subatomic parts are equal

What is the mass in grams of 0.00125 mole of sodium Na=23

Anit [1.1K]

Answer:

0.03g

Explanation:

Given parameters:

Number of moles of Na = 0.00125mole

Unknown:

Mass in grams of Na = ?

Solution:

To find the mass of this substance, we simply multiply the number of moles with the given molar mass of Na.

Mass of Na = number of moles x molar mass

Mass of Na = 0.00125 x 23 = 0.03g

7 0

3 years ago

An example of good peer pressure would include __________. Encouraging your friend to drive you home after you've both been drin

9966 [12]

Encouraging safe and helpful behaviors

7 0

3 years ago

Read 2 more answers

Which best describes the relationships between subatomic particles in any neutral atom? * 1 point the number of electrons equals

Anna71 [15]

Atomic number = protons

Protons = P Electrons = E P = E

Atomic mass = Neutrons + Protons

Atomic number = atomic mass = neutrons

P = E

AM - AN = N

Example:

Calcium = 20 Protons 20P = 20E

Atomic mass - atomic number = neutrons :)

4 0

4 years ago

The correct answer of (43.678)(64.1)

goblinko [34]

Answer:

2,799.7598

Explanation:

If you like my answer than please mark me brainliest thanks

5 0

3 years ago

The sum of the first 10 terms of an arithmetic progression is 120 and the sum of first twenty is 840. find sum of first 30 terms

STatiana [176]

Answer:

The sum of first 30 terms of the arithmetic progression is <u>2160.</u>

Explanation:

For an arithmetic progression, the sum of first $n$ terms with first term as $a$ and common difference $d$ is given as:

$S_n=\frac{n}{2}(2a+(n-1)d)$

Now, it is given that:

$For\ n=10,S_n=120\\For\ n=20,S_n=840$

Now, plug in these values and frame two equations in $a\ and\ d$

$S_{10}=\frac{10}{2}(2a+(10-1)d)\\120=5(2a+9d)\\2a+9d=\frac{120}{5}\\2a+9d=24------------1$

$S_{20}=\frac{20}{2}(2a+(20-1)d)\\840=10(2a+19d)\\2a+19d=\frac{840}{10}\\2a+19d=84-----------2$

Now, we solve equations (1) and (2) for $a\ and\ d$ . Subtract equation (1) from equation (2). This gives,

$2a+19d-2a-9d=84-24\\19d-9d=60\\10d=60\\d=\frac{60}{10}=6$

Now, plug in the value of $d=6$ in equation (1) and solve for $a$ .

$2a+9(6)=24\\2a+54=24\\2a=24-54\\2a=-30\\a=\frac{-30}{2}=-15$

Plug in the values of $a=-15,\ n=30\ and\ d=6$ in the sum formula to find the sum of first 30 terms.

Now, the sum of first 30 terms is given as:

$S_{30}=\frac{30}{2}(2(-15)+(30-1)(6))\\S_{30}=15(-30+29(6))\\S_{30}=15(-30+174)\\S_{30}=15(144)=2160$

Therefore, the sum of first 30 terms of the arithmetic progression is 2160.

4 0

3 years ago