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3 years ago

14

If the pressure, volume, and the number of moles of a gas are known, which is needed to calculate the universal gas constant fro

m the ideal gas law?

1 answer:

umka21 [38]3 years ago

7 0

Answer:

5

Explanation:

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How long will a current of 0.995 A need to be passed through water (containing H2SO4) for 5.00 L of O2 to be produced at STP

DIA [1.3K]

Answer:

24 hours

Explanation:

The computation is shown below:

The needed mole of $O_2$ is

= 5 ÷22.4 = n

Also 1 mole of $O_2$ required four electric charge

Now the charge needed is

= n × 4 × 96,500 C

= 4 × 96,500 × 5 c ÷ 22.4

= 86160.714 C

Now

q = i t

t = q ÷ i

= 86160.714 C ÷ 0.995

= 86593.7 seconds

= 24 hours

Hence, the correct option is A.

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3 years ago

A scientist wrote a report that communicates the steps he performed in an investigation, the data he gathered, and his conclusio

Nookie1986 [14]

Answer:

<u>yes, this is an acceptable practice in research.</u>

<u>Explanation:</u>

Note that, having a different result in one's research does not imply it is automatically invalid. However, because there may have been some errors or limitations in the previous work by the male researcher, it is possible that the later results are more accurate, even though she used the same procedures. She may have been more careful when calculating her results.

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3 years ago

Find the value of c with the correct number of significant

sweet [91]

Answer:

19-73 70-65-46 78-59-86 84-64

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2 years ago

Vitamin C has the formula CxHyOz. You burn 0.486 g of the compound in a combustion analysis chamber and isolate 0.728 g of CO2 a

-Dominant- [34]

Answer:

$C_3H_4O_3$

Explanation:

Hello there!

In this case, according to the given information derived from the combustion analysis, it turns out possible for us to realize that all the carbon comes from the CO2 and all the hydrogen from the H2O, it means we can calculate their moles in the vitamin C as shown below:

$n_C=0.728gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.0165molC\\\\n_H= 0.198gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O}=0.0220molH$

Next, we calculate the grams and moles of oxygen from the grams of C and H in the sample:

$m_O=0.486g-0.0165molC*\frac{12.01gC}{1molC} -0.0220molH*\frac{1.01gH}{1molH}\\\\m_O=0.266gO\\\\n_O=0.266gO*\frac{1molO}{16.00gO} =0.0166molO$

Then, we divide the moles of C, H, O by 0.0165 as the fewest moles in order to calculate the correct mole ratios:

$C=\frac{0.0165}{0.0165}= 1\\\\H=\frac{0.0220}{0.0165}= 1.33\\\\O=\frac{0.0166}{0.0165}= 1$

Finally, we turn them into whole number by multiplying by 3 so that the empirical formula is:

$C_3H_4O_3$

Regards!

3 0

3 years ago

Read 2 more answers

Please help me.. someone

lubasha [3.4K]

The different forms of a gene that decides a characteristic are known as Alleles.

A feature that has different forms in a population are Characteristics.

I believe these are the answers, hope I helped!

6 0

3 years ago