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photoshop1234 [79]
3 years ago
12

The life cycle of a star begins with a cloud of gas and dust called a ________.

Physics
2 answers:
Dahasolnce [82]3 years ago
6 0
<span>The life cycle of a star begins with a cloud of gas and dust called a Nebula
.</span>
mr_godi [17]3 years ago
6 0
I think the correct answer is nebula. The life cycle of a star begins with a cloud of gas and dust called a nebula. It is a cloud of gas which is visible in the night sky as an indistinct bright patch. Hope this answers the question. Have a nice day.
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How can i prove the conservation of mechanical energy?​
FinnZ [79.3K]

Answer:

We can also prove the conservation of mechanical energy of a freely falling body by the work-energy theorem, which states that change in kinetic energy of a body is equal to work done on it. i.e. W=ΔK. And ΔE=ΔK+ΔU. Hence the mechanical energy of the body is conserved

Explanation:

5 0
2 years ago
What is the magnitude of the angular momentum (in kgm2/s) of a 40 g golf ball flying through the air and spinning at 4300 rpm af
sladkih [1.3K]

Answer:

L=0.0045\ kg-m^2/s

Explanation:

Given that,

The mass of a golf ball, m = 40 g = 0.04 kg

Its angular velocity, \omega=4300\ rpm=450.29\ rad/s

The radius of the sphere is 2.5 cm or 0.025 m

We need to find the magnitude of the angular momentum of the ball. It is given by the formula as follows:

L=I\omega

Where I is moment of inertia

For sphere, I=\dfrac{2}{5}mr^2

L=\dfrac{2}{5}mr^2\omega\\\\L=\dfrac{2}{5}\times 0.04\times (0.025)^2\times 450.29\\\\L=0.0045\ kg-m^2/s

So, the magnitude of the angular momentum of the sphere is 0.0045\ kg-m^2/s.

4 0
2 years ago
If 1495 j of heat is needed to raise the temperature of a 351 g sample of a metal from 55.0°c to 66.0°c, what is the specific he
forsale [732]
The amount of heat needed to increase the temperature of a substance by \Delta T is given by
Q= mC_s \Delta T
where m is the mass of the substance, Cs is its specific heat capacity and \Delta T is the increase of temperature.

If we re-arrange the formula, we get
C_s =  \frac{Q}{m \Delta T}
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
C_s =  \frac{1495 J}{(351 g)(66.0^{\circ}C-55.0^{\circ}C)}=0.39 J/g^{\circ}C
6 0
3 years ago
Read 2 more answers
What does this indicate about the claim?
Anton [14]

claim

[klām]

VERB

state or assert that something is the case, typically without providing evidence or proof.

"he claimed that he came from a wealthy, educated family" · [more]

synonyms:

assert · declare · profess · maintain · state · hold · affirm · avow · aver · [more]

NOUN

an assertion of the truth of something, typically one that is disputed or in doubt.

"he was dogged by the claim that he had CIA links" · [more]

synonyms:

assertion · declaration · profession · affirmation · avowal · averment · protestation · representation · contention · submission · case · allegation · pretense · asseveration

a demand or request for something considered one's due.

"the court had denied their claims to asylum"

7 0
3 years ago
Read 2 more answers
When a sinusoidal wave with speed 20 m/s , wavelength 35 cm and amplitude of 1.0 cm passes, what is the maximum speed of a point
vova2212 [387]

To solve this problem it is necessary to apply the concepts related to frequency as a function of speed and wavelength as well as the kinematic equations of simple harmonic motion

From the definition we know that the frequency can be expressed as

f = \frac{v}{\lambda}

Where,

v = Velocity \rightarrow 20m/s

\lambda = Wavelength \rightarrow 35*10^{-2}m

Therefore the frequency would be given as

f = \frac{20}{35*10^{-2}}

f = 57.14Hz

The frequency is directly proportional to the angular velocity therefore

\omega = 2\pi f

\omega = 2\pi *57.14

\omega = 359.03rad/s

Now the maximum speed from the simple harmonic movement is given by

V_{max} = A\omega

Where

A = Amplitude

Then replacing,

V_{max} = (1*10^{-2})(359.03)

V_{max} = 3.59m/s

Therefore the maximum speed of a point on the string is 3.59m/s

8 0
3 years ago
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