Answer: Graph C is the correct option
Explanation:
The question is incomplete, please remember to submit the whole question :)
However, the rest of the question with its corresponding figures is below:
Assume that positive momentum is to the right, which of the following best represents the momentum of the cart of mass m as a function of time before and after the collision?
The initial momentum 
of the cart with mass 
(before the collision) is:
(1) Note the negative sign indicates the direction of cart's velocity (to the left, as seen in the first image attached)
On the other hand, the final momentum 
of both carts (after the inelastic collision) is:
(2)
So, according to this, the correct graph tha best represents the situation is C. Since before the collision the momentum is negative, then both carts slow down after the collision (
), and taking into account the linear momentum is directly proportional to the velocity (although is in the positive direction) is less than .
Answer:
D
A machine can help decrease the input force and increase the output force.
Answer:
The moment of inertia about the rotation axis is 117.45 kg-m²
Explanation:
Given that,
Mass of one child = 16 kg
Mass of second child = 24 kg
Suppose a playground toy has two seats, each 6.1 kg, attached to very light rods of length r = 1.5 m.
We need to calculate the moment of inertia
Using formula of moment of inertia
m = mass of seat
m₁ =mass of one child
m₂ = mass of second child
r = radius of rod
Put the value into the formula
Hence, The moment of inertia about the rotation axis is 117.45 kg-m²
Answer:
14 m/s
Explanation:
The following data were obtained from the question:
Mass = 50 kg
Initial velocity (u) = 0 m/s
Height (h) = 10 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) =?
The velocity (v) with which the person hit the water can be obtained as shown below:
v² = u² + 2gh
v² = 0² + (2 × 9.8 × 10)
v² = 0 + 196
v² = 196
Take the square root of both side
v = √196
v = 14 m/s
Therefore, he will hit the water with a speed of 14 m/s
A) Calling F the intensity of the horizontal force and d the displacement of the block across the floor, the work done by the horizontal force is equal to
b) The work done by the frictional force against the motion of the block is equal to:
Part of these 105.1 Joules of work becomes increase of thermal energy of the block (
), and part of it becomes increase of thermal energy of the floor (
). We already know the increase in thermal energy of the block (38.2 J), so we can find the increase in thermal energy of the floor:
c) The net work done on the block is the work done by the horizontal force F minus the work done by the frictional force (the frictional force acts against the motion, so we must take it with a negative sign):
For the work-energy theorem, the work done on the block is equal to its increase of kinetic energy:
So, we have
