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3 years ago

1. Spring force is proportional to stretch distance, F=kd. Do you expect doubling the stretch distance double the force?

Physics

1 answer:

Solnce55 [7]3 years ago

3 0

Answer:

Yes

Explanation:

The spring force is given as:

F = kd

F is the spring force

K is the spring constant

d is the magnitude of the stretch

Since k is a constant, therefore, doubling the stretch distance will double the force.

Both stretch distance and force applied can be said to be directly proportional to one another.

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The relationship between the resistance and the resistivity of a wire is
$\rho = \frac{AR}{L}$
where
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A is the cross-sectional area
R is the resistance
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the cross-sectional area is given by
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For the new wire, the length L is kept the same (L'=L) while the radius is doubled (r'=2r), so the new resistivity is
$\rho' = \frac{\pi r'^2 R}{L'}= \frac{\pi (2r)^2 R}{L}=4 \frac{\pi r^2 R}{L} = 4 \rho$
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Explanation:

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Answer:

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