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Kruka [31]
2 years ago
12

True or False: The height from which cliff divers jump affects the velocity at which they will fall. Velocity is speed in a cert

ain direction. Include your reasoning with your answer.
Physics
1 answer:
Juli2301 [7.4K]2 years ago
8 0

Answer:

the diver's speed is independent of the launch height.

Explanation:

For this exercise we must use Newton's second law

              fr - W = m a

the friction force has the general form

              fr = b v

Let's analyze this equation to find out what happens with the speed of the distant club.

When jumping, the initial speed is zero, so the friction force is zero and has an acceleration equal to the acceleration of gravity, as the speed increases the friction force increases decreasing the acceleration until it becomes zero, when it arrives at this value the velocity it has is called terminal velocity and this velocity remains fixed in relation to the trajectory.

             fr = W

             v = cte

The distance or time in which this equilibrium is reached is relatively fast, so the diver's speed is independent of the launch height.

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Natasha_Volkova [10]

Answer:

h = height of the hotel room from the ground floor = 237.4m

Explanation:

Change in Potential Energy of tourist = ΔPE = PE2 – PE1 = mgh

PE1 is the potential energy of tourist at the ground floor

PE1 is the potential energy of tourist at the top (hotel room)

Given

PE1 = − 2.01 × 10⁵ J

PE2 = 0J

PE2 – PE1 = mgh

0 – (− 2.01 × 10⁵ J) = mgh

2.01 × 10⁵ J = 86.4×9.8×h

h = 2.01 × 10⁵/(86.4×9.8) = 237.4m

8 0
3 years ago
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Answer:

Torque = 882Nm

Explanation:

Torque = Mg×distance

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Acceleration due to gravity, g=9.8m/s^2

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Torque= 882Nm

6 0
3 years ago
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It’s called mirror universe
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A 5 kg ball of clay is moving with a speed of 25 m/s directly toward a 10 kg ball of clay which is at rest. The two clay balls c
Dafna11 [192]

Answer:

8.3m/s

Explanation:

Given parameters:

mass of clay ball  = 5kg

Speed of clay ball  = 25m/s

mass of clay ball at rest  = 10kg

speed of clay ball at rest  = 0m/s

Unknown:

Velocity after collision  = ?

Solution:

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   m1v1 + m2v2  = v(m1 + m2)

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         125 = 15v

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7 0
2 years ago
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Answer:

Explanation:

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