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Kruka [31]
2 years ago
12

True or False: The height from which cliff divers jump affects the velocity at which they will fall. Velocity is speed in a cert

ain direction. Include your reasoning with your answer.
Physics
1 answer:
Juli2301 [7.4K]2 years ago
8 0

Answer:

the diver's speed is independent of the launch height.

Explanation:

For this exercise we must use Newton's second law

              fr - W = m a

the friction force has the general form

              fr = b v

Let's analyze this equation to find out what happens with the speed of the distant club.

When jumping, the initial speed is zero, so the friction force is zero and has an acceleration equal to the acceleration of gravity, as the speed increases the friction force increases decreasing the acceleration until it becomes zero, when it arrives at this value the velocity it has is called terminal velocity and this velocity remains fixed in relation to the trajectory.

             fr = W

             v = cte

The distance or time in which this equilibrium is reached is relatively fast, so the diver's speed is independent of the launch height.

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Neither side of the equation may be used because there are too many unknown quantities before, during, and after the collision

Explanation:

The impulse theorem states that the change in momentum of an object is equal to the impulse, which is the product between the average force applied and the duration of the collision:

\Delta p = F \Delta t

where

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In this problem, neither side of the equation can be used to measure the change in momentum. In fact:

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Here the final velocity is not known, so it's not possible to use this side of the equation

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brainly.com/question/9484203

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3 years ago
A stone that is thrown vertically upwards was having a velocity of 15m/s after reaches 2/3 of its maximum height. What is the ma
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<em>The correct answer is option</em><em> B.</em> The maximum height that can be reached by the stone is determined as 11.5 m.

<h3>Maximum height attained by the stone </h3>

The maximum height attained by the stone when it is a 2/3 of its total height is calculated as follows;

v² = u² - 2gh

where;

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  • u is initial velocity
  • g is acceleration due to gravity

0 =  u² - 2gh

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h =  u²/2g

h = (15²)/(2 x 9.8)

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h = 11.5 m

Thus, the maximum height that can be reached by the stone is determined as 11.5 m

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