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mr_godi [17]
3 years ago
10

7. Nancy has a mass of 60 kg and sits on the very end of a 3.00 m long plank pivoted in the middle. How much torque must her co-

worker provide on the other end of the plank in order to keep Nancy from falling on the ground?
Physics
1 answer:
netineya [11]3 years ago
6 0

Answer:

Torque = 882Nm

Explanation:

Torque = Mg×distance

But plank's is pivoted ,therefore distance=3/2=1.5m

Mass of Nancy=60jg

Acceleration due to gravity, g=9.8m/s^2

Torque= 60×9.8×1.5

Torque= 882Nm

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The center of gravity of a loaded truck depends on how the truck is packed. If it is 4.0 m high and 2.4 m wide, and its CG is 2.
Vitek1552 [10]

The slope of the road can be given as the ratio of the change in vertical

distance per unit change in horizontal distance.

  • The maximum steepness of the slope where the truck can be parked without tipping over is approximately <u>54.55 %</u>.

Reasons:

Width of the truck = 2.4 meters

Height of the truck = 4.0 meters

Height of the center of gravity = 2.2 meters

Required:

The allowable steepness of the slope the truck can be parked without tipping over.

Solution:

Let, <em>C</em> represent the Center of Gravity, CG

At the tipping point, the angle of elevation of the slope = θ

Where;

tan\left(\theta \right) = \dfrac{\overline{AM}}{\overline{CM}}

The steepness of the slope is therefore;

\mathrm{The \ steepness \  of  \ the  \ slope}= \dfrac{\overline{AM}}{\overline{CM}} \times 100

Where;

\overline{AM} = Half the width of the truck = \dfrac{2.4 \, m}{2} = 1.2 m

\overline{CM} = The elevation of the center of gravity above the ground = 2.2 m

\mathrm{The \ steepness \  of  \ the  \ slope}= \dfrac{1.2}{2.2} \times 100 \approx 54.55\%

tan\left(\theta \right) = \mathbf{\dfrac{2.2}{1.2}} = \dfrac{11}{6}

Elevation \ of \ the \ road \ \theta = arctan\left( \dfrac{6}{11} \right)  \approx 28.6 ^{\circ}

The maximum steepness of the slope where the truck can be parked is <u>54.55 %</u>.

Learn more here:

brainly.com/question/20793607

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3 years ago
Find f0, the magnitude of the upward force on the table due to the leg at (0, 0.
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Assuming that the table has 4 legs. the upward force is equal to the downwardd force. the downward force of the table is the weight of the table. so the upward force is also the weight of the table but in opposite direction, so the upward force in on one leg is 1/4 of the weight of the table
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what material can be stored in a container but can also flow from one container to another and it forms powder after some time​
Greeley [361]

Answer:

I think it is gas.

PLEASE MARK ME BRAINLIEST

4 0
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How much work does and elephant do pulling a circus wagon 1000m with<br> an applied force of 200 N?
RideAnS [48]

Answer:

2000000 J

Explanation: Multiply 200 N by 1000 m

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Electromagnets are created by
VladimirAG [237]

Answer:

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