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dezoksy [38]
3 years ago
10

You kick a soccer ball with a speed of 31 m/s at an angle of 50 degrees. How long does it take the ball to reach the top of its

trajectory?
Physics
1 answer:
Harlamova29_29 [7]3 years ago
3 0

Answer:

Reaches max height at t = 2.42s.

Explanation:

I've assumed we are neglecting air resistance. If not let me know and I'll update.

We want to examine the behaviour of the ball in the y-direction. In the absence of air resistance the only force acting on the ball is gravity, which produces an acceleration in the negative y direction.

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Which statement describes the energy transformation that occurs when a person eats a sandwich to gain energy for a long hike? O
Nataly [62]

Answer:chemical energy is transformed into kinetic energy

Explanation:

7 0
4 years ago
A concave mirror is used as a<br> reflector ina torch light?
4vir4ik [10]

Answer:

A concave mirror is used as a torch reflector. ... When a light bulb is placed at the focus of a concave mirror reflector, the diverging light rays of the bulb are collected by the reflector. These rays are then reflected to produce a strong, parallel-sided beam of light.

Explanation:

8 0
4 years ago
A spaceprobe has an 29.0 m length when measured at rest. What length
elixir [45]

Answer:

The observer sees the space-probe 9.055m long.

Explanation:

Let L_0 be the length of the space-probe when measured at rest, and L be its length as observed by an observer moving at velocity v, then

(1).\: \: L = L_0\sqrt{1-\dfrac{v^2}{c^2} }

Now, we know that L_0 = 29.0m and v = 0.95c, and putting these into (1) we get:

L = 29\sqrt{1-\dfrac{(0.95c)^2}{c^2} }

L = 29\sqrt{1-0.95^2 }

\boxed{L = 9.055m}

Thus, an observer moving at 0.95c observes the space-probe to be 9.055m long.

3 0
3 years ago
Estimate the wavelength corresponding to maximum emission from each of the following surfaces: the sun, a tungsten filament at 2
igomit [66]

Answer

Applying Wein's displacement

\lamda_{max}\ T = 2898 \mu_mK

1) for sun T = 5800 K

      \lambda_{max} = \dfrac{2898}{5800}

      \lambda_{max} = 0.5 \mu_m

2) for tungsten T = 2500 K

      \lambda_{max} = \dfrac{2898}{2500}

      \lambda_{max} = 1.16 \mu_m

3) for heated metal T = 1500 K

      \lambda_{max} = \dfrac{2898}{1500}

      \lambda_{max} = 1.93 \mu_m

4) for human skin T = 305 K

      \lambda_{max} = \dfrac{2898}{305}

      \lambda_{max} = 9.50 \mu_m

5)  for cryogenically cooled metal T = 60 K

      \lambda_{max} = \dfrac{2898}{60}

      \lambda_{max} = 48.3 \mu_m

range of different spectrum

UV ----0.01-0.4

visible----0.4-0.7

infrared------0.7-100

for sun T = 5800

λ              0.01           0.4               0.7                 100

λT             58           2320            4060             5.8 x 10⁵

F                0             0.125             0.491                1

fractions

for UV = 0.125  

for visible = 0.441-0.125 = 0.366

for infrared = 1 -0.491 = 0.509  

8 0
4 years ago
A 14-foot boat operating under oars after dark must show what color light to prevent a collision?
Tomtit [17]
<span>A "White" colored light must be shown by a 14-foot boat that is operating under oars after it is dark, in order to prevent a collision.

Boats which are less than 23 feet cannot exceed a maximum speed of 7 knots. They need to exhibit an all-around white light when it is sailing in the dark.

The other practicable sidelights can also be used instead of the white lights, when they are sailing in international waters.
</span>
7 0
4 years ago
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