Answer:
Approximately 6.8 x 10⁻¹⁵
Explanation:
To be able to get this fraction, there are some things we need to know.
1. The radius of nucleus = 1.0 x 10⁻¹³ cm
2. The radius of hydrogen atom = 52.9 pm
3. Volume of sphere = V1/V2 = (R1/R2)^3
4. 1 picometer (pm) = 10^-10 cm
CHECK ATTACHMENT FOR Step by step solution to the answer
Answer:
Cesium has smallest ionization energy.
Explanation:
Ionization energy is the energy that an atom at ground state must be absorb to release an electron to form a cation. for eg.
H ⇒ 
The unit of ionization energy is 
.
The ionization energy is minimum for cesium & maximum for fluorine.
Ionization energy depends upon the radius of atom. cesium has smallest radius so it has low Ionization energy.
Therefore the cesium has smallest ionization energy.
How many meters per second was it traveling
Answer:
-1
Explanation:
Electrons have a negative charge and protons have a positive charge. (+11) + (-12) = -1
Answer:
A = 13000K has a maximum at lam = 1,9984 10⁻⁷ m = 199.84 nm
, this star is visually separated from the other two by its constant emission spectrum and is not affected by the other two.
we have a fluctuation of the intensity emitted by the stars. Consequently by this fluctuation the amateur astronomer can conclude that this system is made up of two stars.
Explanation:
The radiation of a black body is characterized by its temperature, with Wien's law of displacement we can find the maximum wavelength emitted by each star.
λ T = 2,898 10⁻³
therefore the emission the star of A = 13000K has a maximum at lam = 1,9984 10⁻⁷ m = 199.84 nm
The emission of the premiere is in the ultraviolet light range, as this star is visually separated from the other two by its constant emission spectrum and is not affected by the other two.
The burst with A = 4300K has a bad emission maximum = 6.7395 10⁻⁷ m = 673.95 nm, which corresponds to an emission in the visible in the orange range, giving a blackbody spectrum of this range, but since the emission is formed by two stars, we see that when the two are placed one in front of the other the intensity of the emission must increase significantly and when they are placed next to each other the intensity reaches its minimum, consequently we have a fluctuation of the intensity emitted by the stars.
Consequently by this fluctuation the amateur astronomer can conclude that this system is made up of two stars.
