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4 years ago

Give the formula for RCF using the terms new amount, old amount, equal sign, RCF.

Mathematics

1 answer:

PilotLPTM [1.2K]4 years ago

3 0

Check on go go g le

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Plz help with this question!

Sveta_85 [38]

The answer will be a a is greater

7 0

3 years ago

(1) 4p²q : 10pq²

tiny-mole [99]

Answer: (1) 2p: 5q.

(2) 3:10.

(3) 5:6.

Step-by-step explanation:

To find : Ratio

(1) 4p²q : 10pq²

$=\dfrac{4p^2q}{10pq^2}\\\\=\dfrac{2p^{2-1}}{5q^{2-1}}\\\\=\dfrac{2p}{5q}$

i.e. Simplified ratio of 4p²q : 10pq² is 2p: 5q.

(2) 9 months : 2½ years

1 year = 12 months

$2\dfrac{1}{2}\text{years}=\dfrac{5}{2}\text{years}\\\\=\dfrac{5}{2}\times12=30\text{ months}$

Now, 9 months : 2½ years = $\dfrac{9\text{ months}}{30\text{ months}}=\dfrac{3}{10}$

Hence, Simplified ratio of 9 months : 2½ years is 3:10.

(3) 5 m : 600 cm

1 m = 100 cm

So, 5m = 500 cm

Now, 5 m : 600 cm = $\dfrac{500\ cm}{600\ cm}=\dfrac{5}{6}$

Hence, Simplified ratio of 5 m : 600 cm is 5:6.

7 0

3 years ago

Give your answer in correct number of significant figures: (4.0 x 102 ) (0.04) / 7.2

inysia [295]

Step-by-step explanation:

= (4)(102)

= 408 (408) (0.04) = 16.32 16.32/7.2

= 2.26666667

4 0

2 years ago

Read 2 more answers

If f(x) is a linear function and the domain of f(x) is the set of all real numbers, which statement cannot be true?

IRISSAK [1]

Answer:

can u please add the statements.

Step-by-step explanation:

3 0

3 years ago

If alpha and beta are the zeroes of the polynomial 6x2+x-2 find the value og alpha/beta + beta/alpha

castortr0y [4]

$6x^2+x-2=6x^2+4x-3x-2=2x(3x+2)-1(3x+2)\\\\=(3x+2)(2x-1)\\\\3x+2=0\to x=-\frac{2}{3}\\\\2x-1=0\to x=\frac{1}{2}\\\\\alpha=-\frac{2}{3};\ \beta=\frac{1}{2}\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{-\frac{2}{3}}{\frac{1}{2}}+\frac{\frac{1}{2}}{-\frac{2}{3}}=-\frac{2}{3}\cdot\frac{2}{1}-\frac{1}{2}\cdot\frac{3}{2}=-\frac{4}{3}-\frac{3}{4}\\\\=-\frac{16}{12}-\frac{9}{12}=-\frac{25}{12}=-2\frac{1}{12}$

$use\ Vieta's\ formula:\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}=\frac{\alpha^2+2\alpha\beta+\beta^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2}{\alpha\beta}-2\\\\\alpha+\beta=\frac{-b}{a};\ \alpha\beta=\frac{c}{a}\\\\\frac{(\alpha+\beta)^2}{\alpha\beta}-2=\frac{\left(\frac{-b}{a}\right)^2}{\frac{c}{a}}-2=\frac{b^2}{a^2}\cdot\frac{a}{c}-2=\frac{b^2}{ac}-2$

$6x^2+x-2\\\\a=6;\ b=1;\ c=-2\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{1^2}{6\cdot(-2)}-2=\frac{1}{-12}-2=-2\frac{1}{12}$

7 0

3 years ago