Standard Form

Mathematics

1 answer:

Mashutka [201]3 years ago

3 0

Answer:

I'm not sure if you're solving for a variable but if you have to make it equal zero the answer is:

1.5x-y-1=0

Step-by-step explanation:

First you multiply what's in the parenthesis by 1.5

•y+4=1.5(x+2)

•y+4=1.5x+3

Then you move y and 4 to the other side by subtracting y and 4 from both sides

•4=1.5x-y+3

•0=1.5x-y-1

You might be interested in

PLEASE ANSWER At a basketball game, 75% of people attending were supporting the home team, while 25% were supporting the visitin

Rufina [12.5K]

75% = 0.75

750 people / 0.75 = 1,000 people

There were 1,000 total people attending the game

6 0

3 years ago

Read 2 more answers

In the number 432.785 which number is the hundredths digit

dimulka [17.4K]

The number in the hundredths digit is 8.

7 0

3 years ago

Read 2 more answers

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$