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Sever21 [200]
2 years ago
9

Help me with this questions please

Mathematics
1 answer:
mixas84 [53]2 years ago
4 0
I) f(2)=1.5
ii) f(x)=0 ⇒ x=1.2
iii) k=-1
iv) x=1 ⇒ f(x)=1
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3 0
3 years ago
Hi what is the answer for this?
saw5 [17]
This is a common factor problem.

Pencils come in a pack of 12
Erasers come in a pack of 10

First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3

So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
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So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
60/12=5 packs of pencils
60/10= 6 packs of erasers

I hope this helps. Let me know if you have any questions!!
5 0
3 years ago
Read 2 more answers
If the average (arithmetic mean) of 10,20,30,40, and x is 60, what is the value of x​
Lilit [14]

60 =  (10 + 20 + 30 + 40 + x)/5

300 = 100 + x

x = 200

Answer: 200

8 0
2 years ago
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