Help me with this questions please

How do u factor out the coefficient of the variable??? -6z + 12 equals what

Bezzdna [24]

-6z+ 12
= -6(z -2) (distributive property)

The final answer is -6(z -2)~

7 0

3 years ago

Two chemists working for a chicken fast-food company, have been producing a very popular sauce. Let’s call then Jesse and Mr. Wh

a_sh-v [17]

Answer:

Check the explanation

Step-by-step explanation:

Let $\overline{x}$ and $\overline{y}$ be sample means of white and Jesse denotes are two random variables.

Given that both samples are having normally distributed.

Assume $\overline{x}$ having with mean $\mu_{1}$ and $\overline{y}$ having mean $\mu_{2}$

Also we have given the variance is constant

A)

We can test hypothesis as

$H0: \mu_{1} = \mu_{2}H1: \mu_{1} > \mu_{2}$

For this problem

Test statistic is

$T=\frac{\overline {x}-\overline {y}}{s\sqrt{\frac {1}{n1} +\frac{1}{n2}}}$

Where

$s=\sqrt{\frac{(n1-1)*s1^{2}+(n2-1)*s2^{2}}{n1+n2-2}}$

We have given all information for samples

By calculations we get

s=2.41

T=2.52

Here test statistic is having t-distribution with df=(10+7-2)=15

So p-value is P(t15>2.52)=0.012

Here significance level is 0.05

Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.

We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.

3 0

3 years ago

In a pack of 52 cards, 4 of the cards are kings. the first card is picked, the results are recorded and the card is returned to

Ulleksa [173]

Total cards = 52

Total kings = 4

P(2 kings) = (4/52)(4/52) = 1/169

Answer : 1/169

8 0

4 years ago

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz. An ornithologi

il63 [147K]

Answer:

The formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.7}{2} = 0.15$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.15 = 0.85$ , so Z = 1.037.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz.

This means that $\sigma = 0.04$ .

Sample of 10 birds:

This means that $n = 10$ .

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.037\frac{0.04}{\sqrt{10}}$

$M = 0.013$

The lower end of the interval is the sample mean of $\overline{x}$ subtracted by M.

The upper end of the interval is the sample mean of $\overline{x}$ added to M.

Then, the formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

8 0

3 years ago

Solve for x: 2 over 3 equals 8 over quantity x plus 6

SashulF [63]

Answer:

x = 40/3

Step-by-step explanation:

2/3 = (8/x) + 6

-6 -6

2/3 - 6 = -16/3

-16/3 = 8/x

*x *x

(-16/3)x = 8

+16/3 +16/3

x = 40/3

7 0

3 years ago

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