3 years ago

Values that are solutions to the inequality x2 + 3x – 4 > 0.

1 answer:

8 0

$x^2 + 3x - 4 > 0\\
x^2-x+4x-4>0\\
x(x-1)+4(x-1)>0\\
(x+4)(x-1)>1\\
x\in(-\infty,-4)\cup(1,\infty)$

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BlackZzzverrR [31]

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