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Ilya [14]
3 years ago
14

Values that are solutions to the inequality x2 + 3x – 4 > 0.

Mathematics
1 answer:
natka813 [3]3 years ago
8 0

x^2 + 3x - 4 > 0\\
x^2-x+4x-4>0\\
x(x-1)+4(x-1)>0\\
(x+4)(x-1)>1\\
x\in(-\infty,-4)\cup(1,\infty)

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Step-by-step explanation:

To solve this problem use the law of the sines.

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