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Ilya [14]
3 years ago
14

Values that are solutions to the inequality x2 + 3x – 4 > 0.

Mathematics
1 answer:
natka813 [3]3 years ago
8 0

x^2 + 3x - 4 > 0\\
x^2-x+4x-4>0\\
x(x-1)+4(x-1)>0\\
(x+4)(x-1)>1\\
x\in(-\infty,-4)\cup(1,\infty)

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Use the x-intercept method to find all real solutions of the equation. x^3-9x^2+11x+21=0
IgorLugansk [536]
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Step-by-step explanation:

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3 years ago
(If A(2, -3), B(3,-2) and point C divides the line segment AB in the ratio of 1: 2, find OC.)​
Anna007 [38]

Answer:

A(2, -3) and B(3, -2), o(0, 0) Let C(x, y)

Here c divide AB line in the ratio of 1:2

From the line intersection law, we get x=(m1×x2+m2×x1)/(m1+m2)

and y=(m1×y2+m2×y1)/(m1+m2)

where m1=1, m2=2, x1=2, x2=3, y1=-3, y2=-2;

so x=(3+4)/3

  or, x=7/3;

y=(-2-6)/3

 or, y=-8/3;

so, oc=√((0-7/3)²+(0-(-8/3))²)

oc=3.54

7 0
2 years ago
What is the value of s in the equation 4(2s − 1) = 7s + 12? <br> 12<br> 16<br> 32<br> 34
erastova [34]
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3 0
3 years ago
Read 2 more answers
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