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BartSMP [9]
3 years ago
6

What is the value of s in the equation 4(2s − 1) = 7s + 12? 12 16 32 34

Mathematics
2 answers:
Eva8 [605]3 years ago
4 0

The answer to the equation is in the image below.

Hope this helps!

erastova [34]3 years ago
3 0
You start by distributing: 8s-4=7s+12
Combine like terms: 8s-7s=12+4
Solve and get your answer: s=16
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Which number is greater 87 or 13.688
nexus9112 [7]
87 is greater than 13.688


3 0
3 years ago
Read 2 more answers
The ratio of adults to children attending a new exhibit at the museum was found to be 8:5. Based on this ratio, if 390 people at
Zinaida [17]
8x+5x=390\\
13x=390\\
x=30\\\\
5x=5\cdot30=\boxed{150}
6 0
3 years ago
Read 2 more answers
Stephon makes the following statements: statement 1 lim x -3 f(x) exists and is equal to 1 statement 2 lim x 1 f(x) exists and i
Mandarinka [93]

Neither statement 1, nor statement 2 are correct

The given Stephon's statements are;

Statement 1; \mathbf{\lim \limits  _{x \to -3} f(x)}  \ \mathbf{Exist} \ and \mathbf{\lim \limits  _{x \to -3} f(x) = 1}

Statement 2; \mathbf{\lim \limits  _{x \to 1} f(x)}  \ \mathbf{Exist} \ and \mathbf{\lim \limits  _{x \to 1} f(x) = 1}

The analysis of the graph and reason for the answer

From the graphed line on the left of the y-axis, we have an open circle at x = -3, and an arrow at the other end pointing towards negative infinity, (-∞) which indicates that the domain is -∞ ≤ x < -3, therefore, at x = -3, f(x) does not exist, therefore, we can write the following statement

The limits of the domain and range of the graph includes;

\mathbf{\lim \limits  _{x \to -3} f(x)} = \mathbf{Does \ not \ exist}

f(x) = Defined for -∞ ≤ x < -3

Similarly, from the graphed line on the right of the y-axis, we have an open circle at x = 1 and an arrow at the other end of the line f(x) = 4 pointing towards positive (+∞) infinity, which indicates the domain and the graph of the function is 1 < x ≤ ∞ , therefore, f(x) does not exist at x = 1, and we can write

\mathbf{\lim \limits  _{x \to 1} f(x)} = \mathbf{Does \ not \ exist}

From we above, we have that neither statement 1, nor statement 2 are correct

Learn more about open and closed circles on graph lines

brainly.com/question/8648835

4 0
3 years ago
Solve the equation : <br><img src="https://tex.z-dn.net/?f=%20%5Ccos%28x%29%20-%20%20%5Csin%28x%29%20%20%3D%20%20%5Csqrt%7B2%20%
Debora [2.8K]

Answer:

General solution is

 x = n \pi + \frac{\pi }{8}

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  cos x - sin x = √2 cos (3 x)

Dividing '√2' on both sides , we get

\frac{1}{\sqrt{2} } cos (x) - \frac{1}{\sqrt{2} } sin (x) = \frac{\sqrt{2} cos (3 x)}{\sqrt{2} }

we will use trigonometry formulas

a) Cos ( A + B) = Cos A Cos B - sin A sin B

b)  cos \frac{\pi }{4} = \frac{1}{\sqrt{2} }

<u><em>Step(ii):-</em></u>

<u><em></em></u>\frac{1}{\sqrt{2} } cos (x) - \frac{1}{\sqrt{2} } sin (x) = \frac{\sqrt{2} cos (3 x)}{\sqrt{2} }<u><em></em></u>

cos (\frac{\pi }{4} ) cos x - sin(\frac{\pi }{4} ) sin x = cos 3x

cos (\frac{\pi }{4}+x ) = cos 3 x

<u><em>Step(iii):-</em></u>

<u><em>General solution of  cos x = cos ∝  is  x = 2 nπ+∝</em></u>

<u><em>we have </em></u> cos (\frac{\pi }{4}+x ) = cos 3 x

The general solution of  cos (\frac{\pi }{4}+x ) = cos 3 x is

⇒  3 x   = 2 n \pi  + (\frac{\pi }{4}+x )

⇒ 3 x- x = 2 n \pi + \frac{\pi }{4}

 2x = 2 n \pi + \frac{\pi }{4}

<em><u>final answer</u></em>:-

General solution is

 x = n \pi + \frac{\pi }{8}

             

8 0
3 years ago
In the net of a cylinder, one dimension of the rectangle is the same as the circumference of each circular base. Is this true or
Dominik [7]

Answer:

True.

Step-by-step explanation:

When we look at a cylinder, it has be observed that it has 3 parts or 3 shapes to it.

These 3 parts or shapes are referred to as the net of a cylinder.

This 3 parts include

a. A circle at the top

b. A circle at the bottom.

c. A rectangle.

The circle at the bottom gives us the base of the cylinder while the rectangle is curved when forming the cylinder and it is due to this that we have the curved surface area of the cylinder.

It is important to know that there is a relationship between the length of one of the edges of the rectangle and the circumference of the base of the cylinder such that, the length of one of the edges of the rectangle is equal to or equivalent to the circumference of each circular base.

5 0
3 years ago
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