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Karo-lina-s [1.5K]
3 years ago
14

The number three ball moves off with a velocity of 5 m/s. What is the final velocity and direction of the eight ball?

Physics
1 answer:
Keith_Richards [23]3 years ago
6 0
7 and a half millimeters long
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A force of 400-N pushes on a 25-kg box horizontally. The box accelerates at 9 m/s? Find the coefficient of kinetic friction betw
umka2103 [35]

Answer:

<h3>0.69</h3>

Explanation:

Using the Newtons law of motion;

\sum Fx = ma_x\\Fm - Ff = ma_x

Fm is the moving force = 400N

Ff is the frictional force = μR

μ is the coefficient of kinetic friction

R is the reaction = mg

m is the mass

a is the acceleration

The equation becomes;

Fm - \mu R = ma_x\\Fm - \mu mg = ma_x\\400- \mu (25)(9.8) = 25(9)\\400 - 254.8 \mu = 225\\- 254.8 \mu = 225 - 400\\- 254.8 \mu = -175\\ \mu = \frac{-175}{- 254.8} \\\mu = 0.69

Hence the coefficient of kinetic friction between the box and floor is 0.69

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3 years ago
What is the kinetic energy when the pendulum is at the halfway point
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The answer is 0 , hope this helps
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A negative charge is moving from point A to point B to the RIGHT in an area where there is a constant electric field also pointi
Aneli [31]

Answer:

Explanation:

In the electric field pointing right , force on the electron will be towards left . Since charge is moving towards right so it is doing some work against the force . Hence its potential energy will increase. Whenever a work is done against a force , the work done is converted into potential energy in conservative field. Electric field is also a conservative field.

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Un movil pasa por el punto A en direccion hacia B (350cm más adelante) y, luego, sigue hasta el punto C. Sabiendo que pasa por B
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Explanation:

PRIMERO HACES EL RECUENTO DEL TIEMPO Y LO CONVIERTES EN

SEGUNDOS Y ENTONCES

<em>t</em> = 227 s      t_{AB} = 227 S - 38 s = 189 s

t_{BC} = 38 s

LUEGO USANDO LA ECUACIÓN DE GALILEO GALILEI SSUPONIENDO

QUE EL MOVIL VIAJA A VELOCIDAD CONSTANTE

<em>v</em> = 3.50 m/189 s = 0.0185 m/s

PARA LA DISTANCIA NTRE B Y C

x_{BC} = 0.0185 m/S( 38 s) = 0.703 m

LA HORA EN QUE EL MOVIL PASA POR A ES

11:43:15 - 38 s - 189 s = 11:39:29

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Give two examples of human activity that affect the earth systems
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