Answer:
The voltage across the capacitor = 0.8723 V
Explanation:
From the question, it is said that the coil is quickly pulled out of the magnetic field. Therefore , the final magnetic flux linked to the coil is zero.
The change in magnetic flux linked to this coil is:
= 0 - BA cos 0°
![\delta \phi =-BA \\ \\ \delta \phi =-B( \pi r^2) \\ \\ \delta \phi =(1.0 \ mT)[ \pi ( \frac{d}{2} )^2]](https://tex.z-dn.net/?f=%5Cdelta%20%5Cphi%20%20%3D-BA%20%5C%5C%20%5C%5C%20%5Cdelta%20%5Cphi%20%20%3D-B%28%20%5Cpi%20r%5E2%29%20%5C%5C%20%5C%5C%20%5Cdelta%20%5Cphi%20%20%3D%281.0%20%20%5C%20mT%29%5B%20%5Cpi%20%28%20%5Cfrac%7Bd%7D%7B2%7D%20%29%5E2%5D)
![\delta \phi =(1.0 \ mT)[ \pi ( \frac{0.01}{2} )^2]](https://tex.z-dn.net/?f=%5Cdelta%20%5Cphi%20%20%3D%281.0%20%20%5C%20mT%29%5B%20%5Cpi%20%28%20%5Cfrac%7B0.01%7D%7B2%7D%20%29%5E2%5D)
Using Faraday's Law; the induced emf on N turns of coil is;
Also; the induced current I = 
The voltage across the capacitor can now be determined as:
= 
= 0.8723 V
-- Momentum is (mass) x (speed).
Object B has 1.5 times as much momentum as Object A has.
-- Kinetic energy is (1/2) x (mass) x (speed) .
Object B has 1.5 times as much kinetic energy as Object A has.
-- If they would both stop long enough to get on the scale,
Object B would weigh 1.5 times as much as Object A does.
I think the correct answer is bacteria
It depends on what speed you are going at. Assuming you are in our fastest spacecraft as of now which has a speed of 17,500 mph
1 light second = 186,282 mph
There are <span>31,536,000 in one year so 17,500x=31,534,000 and your answer would be in years. It would take you roughly 1802 years.</span>
(Sorry about mph I'm American.)
Answer:
2.9 N
Explanation:
When the separation distance, r, is 0.5 m, the electrostatic force is 0.32 N. Electrostatic force is given as:
F = (k * q1 * q2) / r²
Where F = force acting on the balloons
k = Coulombs constant
Therefore:
0.32 = (k * q1 * q2) / 0.5²
=> k * q1 * q2 = 0.32 * 0.5² ------------(1)
When the distance is decreased by 3, that is r = r/3 = 0.5/3
F = (k * q1 * q2) / (0.5/3)² ------------(2)
Putting (1) into (2):
=> F = (0.32 * 0.5²) / (0.5/3)²
F = (0.32 * 0.5² * 3²) / 0.5²
F = 2.9 N
Therefore, the force would be 2.9 N
