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4 years ago

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A negative charge is moving from point A to point B to the RIGHT in an area where there is a constant electric field also pointi

ng to the RIGHT. Does the potential energy of the charge increase, decrease or remains the same?

1 answer:

Aneli [31]4 years ago

3 0

Answer:

Explanation:

In the electric field pointing right , force on the electron will be towards left . Since charge is moving towards right so it is doing some work against the force . Hence its potential energy will increase. Whenever a work is done against a force , the work done is converted into potential energy in conservative field. Electric field is also a conservative field.

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A cart is moving at 55 m/s at an angle of 25° to the ground. Determine the horizontal component.

Elodia [21]

Answer:

<em>The horizontal component of the velocity is 49.85 m/s.</em>

Explanation:

<u>Rectangular Components of a Vector</u>

A 2D vector can be expressed in several forms. The rectangular form gives its two components, one for each axis (x,y). The polar form gives the components as the pair (r,θ) being r the magnitude and θ the angle.

When the magnitude and angle of the vector are given, the rectangular components are calculated as follows:

$v_x=v\cos\theta$

$v_y=v\sin\theta$

Where v is the magnitude of the vector and θ is the angle with respect to the x positive direction.

The cart is moving at v=55 m/s at θ=25°, thus:

$v_x=55\cos 25^\circ$

$v_x=49.85\ m/s$

The horizontal component of the velocity is 49.85 m/s.

7 0

3 years ago

A car accelerates at a rate of 3 m/s^2. If its original speed is 8 m/s, how many seconds will it take the car to reach a final s

kkurt [141]

Answer:

$\Large \boxed{\mathrm{5.67 \ seconds }}$

Explanation:

$\displaystyle \mathrm{acceleration \ = \ \frac{final \ velocity - initial \ velocity }{elapsed \ time}}$

$\displaystyle A \ = \ \frac{V_f - V_i }{t}$

$\displaystyle 3 \ = \ \frac{25 - 8 }{t}$

$\displaystyle 3 \ = \ \frac{17 }{t}$

$\displaystyle t \ = \ \frac{17 }{3} \approx 5.67$

4 0

3 years ago

For a wavelength of 420 nm, a diffraction grating produces a bright fringe at an angle of 24°. For an unknown wavelength, the sa

Inessa [10]

Answer:

649.8420 nm

Explanation:

We have given $\Theta _1=24^{\circ} \ and\ \Theta _2=39^{\circ}$

$\lambda _1=420\ nm$ we have to find unknown wavelength that is $\lambda _2$

The condition for constructive interference is $dsin\Theta =n\lambda$

Where d is distance between slits $\Theta$ is angle of emergence and n is order of maxima

Using constructive interference equation

$dsin\Theta _1=n\lambda _1$ ---------eqn 1

$dsin\Theta _2=n\lambda _2$ ---------eqn 2

On dividing eqn 1 by eqn 2

$\frac{\lambda _1}{\lambda _2}=\frac{sin\Theta _1}{sin\Theta _2}$

$\frac{420}{\lambda _2}=\frac{sin24^{\circ}}{sin39^{\circ}}$

$\lambda _2=649.8420\ nm$

7 0

3 years ago

Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 8.0

zloy xaker [14]

Answer: $278\ Hz$

Explanation:

Given

Distance between two speakers is 8 m

Man is standing 12 away from the wall

When the person moves 3 parallel to the wall

the parallel distances from the speaker become 4+3, 4-3

Now, the difference of distances from the speaker is

$\Delta d=\sqrt{12^2+(4+3)^2}-\sqrt{12^2-(4-3)^2}\\\Delta d=1.85\ m$

Condition for destructive interference is

$\Delta d=(2n-1)\dfrac{\lambda }{2}=(2n-1)\dfrac{\nu }{2f}\\\\\Rightarrow f=(2n-1)\dfrac{v}{2\Delta d}$

for second destructive interference; n=2

$\Rightarrow f=(2\times 2-1)\dfrac{343}{2\times 1.85}=278.10\approx 278\ Hz$

4 0

3 years ago

The larger the mass of a star, the higher the internal pressures. Higher internal pressures causes higher temperatures and it is

hram777 [196]

The types of fusion that occurs in stars are:

proton-proton fusion - stars with temperatures less than 15 million Kelvin and masses of 0.08 solar mass or more.

carbon cycle fusion - occurs in stars with temperatures of 15 million Kelvin or more and masses of 4.0 solar mass or more

helium fusion - occurs in stars with temperatures of 100 million Kelvin or more and masses of 0.5 solar mass or more

<h3>What is a nuclear fusion reaction?</h3>

A nuclear fusion is reaction in which nucleus of small atoms combine together to produces atoms of larger nucleus.

The types of nuclear fusion that can occur in a star include;

Proton-proton fusion - occur in stars with core temperatures less than 15 million Kelvin and masses of 0.08 solar mass or more.
Carbon cycle fusion occurs in stars with core temperatures greater than 15 million Kelvin having masses of 4.0 solar mass or more.
Helium fusion - occurs in stars with core temperatures greater than 100 million Kelvin and masses of 0.5 solar mass or more

In conclusion, the types of fusion that occur in stars are proton-proton fusion, carbon cycle fusion and helium fusion.

Learn more about nuclear fusion at: brainly.com/question/982293

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6 0

2 years ago