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melisa1 [442]
4 years ago
14

A negative charge is moving from point A to point B to the RIGHT in an area where there is a constant electric field also pointi

ng to the RIGHT. Does the potential energy of the charge increase, decrease or remains the same?
Physics
1 answer:
Aneli [31]4 years ago
3 0

Answer:

Explanation:

In the electric field pointing right , force on the electron will be towards left . Since charge is moving towards right so it is doing some work against the force . Hence its potential energy will increase. Whenever a work is done against a force , the work done is converted into potential energy in conservative field. Electric field is also a conservative field.

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What are some of the major differences between the ancient Olympics and modern-day Olympics? List and describe at least two diff
umka21 [38]

Answer:

1

The ancient Olympic games only allowed people of Greek descent to participate. The Salt Lake City Olympics featured 2600 athletes from 77 countries. Only a few hundred athletes participated in the ancient games.

#2

Only men were allowed to compete in the ancient Greek games. Athletic training in ancient Greece was part of every free male citizen's education. The first women to compete in the Olympics were Marie Ohnier and Mme. Brohy. They participated in croquet games in the 1900 Olympics.

3 0
3 years ago
Give one example of a thermodynamic cycle that does not account for the carnot efficiency.
Arturiano [62]

Thermo-Electrochemical converter (UTEC) is a thermodynamic cycle that does not account for the Carnot Efficiency.

The Carnot cycle is a hypothetical cycle that takes no account of entropy generation. It is assumed that the heat source and heat sink have perfect heat transfer. The working fluid also remains in the same phase, as opposed to the Rankine cycle, in which the fluid changes phase. A practical thermodynamic cycle, such as the Rankine cycle, would achieve at most 50% of the Carnot cycle efficiency under similar heat source and heat sink temperatures.

<h3>What is Thermo-Electrochemical converter?</h3>

In a two-cell structure, a thermo-electrochemical converter converts potential energy difference during hydrogen oxidation and reduction to heat energy.

It employs the Ericsson cycle, which is less efficient than the Carnot cycle. In a closed system, it converts heat to electrical energy. There are no external input or output devices.

This means there will be no mechanical work to be done, as well as no exhaust. As a result, Carnot efficiency is not taken into account in this cycle. Carnot efficiency is accounted for by other options such as turbine and engine.

Learn more about Thermo-Electrochemical converter here:

brainly.com/question/13040188

#SPJ4

4 0
2 years ago
What are the two conditions for equilibrium of a rigid body? how would this experiment demonstrate their validity?.
Naddik [55]

Answer:

They're are Conditions .... (L00K D0WN.)

Explanation:

Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium.

4 0
3 years ago
Help!?!?!??!!?!?!?!?!?!?!
Marysya12 [62]

D only kinetic energt because if it had heluim or any thing jt will float up

4 0
3 years ago
Two drag cars race. They line up at the starting line at rest. The winning car accelerates at a constant rate a and reaches the
Mila [183]

Answer:d=\frac{v^2}{8a}

Explanation:

Given

winning car accelerates with a and its final velocity is v

considering they both start from rest

time taken by winning car is

v=u+at

where u=initial velocity

a=acceleration

t=time

v=at

t=\frac{v}{a}

Now loosing car is accelerating with \frac{a}{4}

Distance traveled by loosing car in time t

s_1=ut+\frac{at^2}{2\cdot 4}

s_1=0+\frac{a}{8}\times (\frac{v}{a})^2

s_1=\frac{v^2}{8a}

Thus distance d traveled by loosing car is given by d=\frac{v^2}{8a}

5 0
4 years ago
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