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melisa1 [442]
4 years ago
14

A negative charge is moving from point A to point B to the RIGHT in an area where there is a constant electric field also pointi

ng to the RIGHT. Does the potential energy of the charge increase, decrease or remains the same?
Physics
1 answer:
Aneli [31]4 years ago
3 0

Answer:

Explanation:

In the electric field pointing right , force on the electron will be towards left . Since charge is moving towards right so it is doing some work against the force . Hence its potential energy will increase. Whenever a work is done against a force , the work done is converted into potential energy in conservative field. Electric field is also a conservative field.

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Answer:

Length = 2.32 m

Explanation:

Let the length required be 'L'.

Given:

Resistance of the resistor (R) = 3.7 Ω

Radius of the rod (r) = 1.9 mm = 0.0019 m [1 mm = 0.001 m]

Resistivity of the material of rod (ρ) = 1.8\times 10^{-5}\ \Omega\cdot m

First, let us find the area of the circular rod.

Area is given as:

A=\pi r^2=3.14\times (0.0019)^2=1.13\times 10^{-5}\ m^2

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Express this in terms of 'L'. This gives,

\rho\times L=R\times A\\\\L=\frac{R\times A}{\rho}

Now, plug in the given values and solve for length 'L'. This gives,

L=\frac{3.7\ \Omega\times 1.13\times 10^{-5}\ m^2}{1.8\times 10^{-5}\ \Omega\cdot m}\\\\L=\frac{4.181}{1.8}=2.32\ m

Therefore, the length of the material required to make a resistor of 3.7 Ω is 2.32 m.

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What is the continuous flow of electric charge?
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