3 years ago

Please help me, anyone!!!

2 answers:

5 0

Even after reading the question, I don't understand it.
The speed of light is 299,792,458 meters per second, and that is the "speed limit" of the universe. Nothing moves faster. (Not even tachyons.)

liq [111]3 years ago

4 0

<span>tachyons are a lot faster than the speed of light </span>

You might be interested in

A student switches the torch on and sees that it gives out a bright light.

garik1379 [7]

Answer:

no more fire duhh

Explanation:

3 0

2 years ago

Read 2 more answers

Sort the processes based on the type of energy transfer they involve.??

klemol [59]

The 1st one goes two added sodoes the second one then the third goes to removed then the fourth goes to added and the rest go to removed

3 0

3 years ago

Read 2 more answers

A quarterback throws a football 40 yards in 4 seconds.what is the average speed the football

lions [1.4K]

The answer is 10 yards per second

8 0

3 years ago

Read 2 more answers

Here, mA = 3.65 kg and mB = 7.05 kg. The string connecting the two objects is of negligible mass and the pulley is frictionless.

mr_godi [17]

Answer:

The magintude of the acceleration for both objects is $3.11m/s^2$

Explanation:

Drawing a free body diagram on the two boxes we can analyze the system more easily.

we can take the acceleration going up as positive for reference purposes.

for mA let's suppose that is ascending so:

$T_A-m_A*g=m_A*a$

and for mB (descending):

$T_B-m_B*g=-m_B*a$

$T_A=T_B$

because the two boxes has the same acceleration because they are attached together:

$m_B*g-m_B*a-m_a*g=m_a*a\\(m_B-m_A)*g=(m_a+m_B)*a\\a=\frac{(7.05kg-3.65kg)*9.8m/s^2}{3.65kg+7.05kg}\\\\a=3.11m/s^2$

So the magintude of the acceleration for both objects is $3.11m/s^2$

5 0

2 years ago

This is a Physics practice question. How do i solve it?

Elena-2011 [213]

Answer:

P = 140000 [Pa]

Explanation:

To solve this problem we must remember that pressure is defined as the relationship between Force on the area of a body.

In this particular problem, we are given the force acting on the upper surface of the block, including the force exerted by the atmospheric pressure.

P = F/A

where:

P = pressure [Pa] (units of Pascals)

F = force = 3.5*10⁴ [N]

A = area = 0.25 [m²]

P = 3.5*10⁴/0.25

P = 140000 [Pa]

7 0

3 years ago