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harina [27]
3 years ago
5

Can anyone do my imagine math and get me 6 certificates (pass the lessons) pleaseeeeeee I need it today before 5

Mathematics
1 answer:
zlopas [31]3 years ago
5 0

IF ANYONE knows Imagine Math or has the site, Please help, she needs it and were trying to figure the questions....AGAIN please answer ASAP!  :)

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What is the momentum of 200kg portable if it travels 50 meters in 5seconds
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Momentum  = mass * velocity

50 meters in 5 seconds = 50/5  = 10 m / second

Required momentum  = 200*10  = 2,000 

I cant remember how to write the units for this.
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Factor the expression.<br> 30-4n
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Hope this is what you are looking for the answer is 2(15-2n)
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To describe a sequence of transformations that maps triangle ABC onto triangle a"b"c", a student starts with a reflection over t
Paha777 [63]

i dont quite get the question but...

i guess this is how it is.

Take the mirror image of∆ABC Through the a line through the point y=3.

The new ∆ABC would have point C=(4,2)

B=(3,-6) A=(1,-3)

Now shifting the ∆ABC one unit (<em>i.e. 2 acc. to the graph as scale is 1 unit =2</em>) towards right ( or <em>adding 2 to the x coordinates of ∆ABC)</em>

We get the Coordinates of triangle ABC as A=(3,-3) B=(5,-6) C=(6,2).

This coordinate is the same coordinates of ∆A"B"C".

Hope it helps...

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8 0
3 years ago
I have a question about brainly
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3 years ago
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A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
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