What happens to the particles in a medium when waves propagate through the medium

A wire with a circular cross section and a resistance R is lengthened to 9.66 times its original length by pulling it through a

damaskus [11]

Answer:

The resistance of the wire after it is stretched is 93.31R.

Explanation:

Resistance is the property of the material to oppose the current flow through it. It is given by the relation :

R = (ρl)/A

Here ρ is resistivity, l is length of wire and A is the area of the wire.

Let l₀, and A₀ are the original length and original circular cross section area of the wire. while l₁ and A₁ are the new length and new circular cross section area of the wire.

Volume of the original wire, V₀ = A₀ x l₀

Volume of the new wire, V₁ = A₁ x l₁

According to the problem. volume remain same. So,

V₀ = V₁

A₀ x l₀ = A₁ x l₁

It is given that l₁ = 9.66 x l₀. Substitute this value in the above equation;

A₀ x l₀ = A₁ x 9.66 x l₀

A₁ = A₀/9.66

Resistance of the original wire, R = (ρl₀)/A₀

Resistance of the new wire, R₁ = (ρl₁)/A₁

Substitute the value of l₁ and A₁ in the above equation.

R₁ = (ρ x l₀ x 9.66)/(A₀/9.66) = 93.31 x (ρl₀)/A₀

But (ρl₀)/A₀ = R. hence,

R₁ = 93.31 R

8 0

3 years ago

I can’t figure this out!!! Answer what you can , please.

tigry1 [53]

a/b. The ball has velocity vector at time $t$

$\vec v=(v_x,v_y)=(v_0\cos63^\circ,v_0\sin63^\circ-gt)$

where $v_0=16\dfrac{\rm m}{\rm s}$ is the ball's initial speed and $g=9.8\dfrac{\rm m}{\mathrm s^2}$ .

c. At its highest point, the ball has 0 vertical speed. This occurs when

$v_0\sin63^\circ-gt=0\implies t=1.5\,\mathrm s$

d. Recall that

${v_y}^2-{v_{0y}}^2=-2g\Delta y$

so that at its highest point,

$0^2-(v_0\sin63^\circ)^2=-2g\Delta y\implies\Delta y=10\,\mathrm m$

e. This is just twice the time it takes for the ball to reach its maximum height, $t=2.9\,\mathrm s$ .

f. The ball's horizontal position after time $t$ is

$v_0\cos63^\circ\,t$

so that after the time found in part (f), the ball has traveled

$v_0\cos63^\circ(2.9\,\mathrm s)=11\,\mathrm m$

4 0

4 years ago

Math the following to definitions

Leona [35]

Hi,
The answer should be:
Vector 5
Magnatude 4
Weight 1
Mass 2
Net force 6
Force 3

Hope this helps!

6 0

3 years ago

Explain how this increases their efficiency. Explain how this increases their efficiency. Antireflective coating causes the phas

sweet [91]

Answer:

c) True. If the coating cancels the light requested by the reflection, so there is more energy to enter the cell and therefore its efficiency increases

Explanation:

This exercise asks to analyze the effect of the antireflective coating on the efficiency of solar cells.

Let's start by expressing the expression for the interference of two light beams taken at when

* the phase change introduced when passing from air to 180º film

* the wavelength change by the refractive index of the film ln = lo / n

therefore the expression for destructive interference is

2 n t = m λ

where m is an integer

with these concepts we can analyze the different statements

a) False. Phase shift does not change the wavelength of light

b) False. The refractive index of the solar cell is not affected by the refractive index of the film since the two materials do not mix.

c) True. If the coating cancels the light requested by the reflection, so there is more energy to enter the cell and therefore its efficiency increases

d) false. In solar cells the incidence is almost normal, therefore the effect of refraction (separation of colors for different angles) is very small

7 0

3 years ago

A(n)___________is a combination of substances that are combined physically but not chemically.

Sedaia [141]

<span>The answer is heterogeneous mixture. A heterogeneous mixture is a combination of substances that are combined physically but not chemically. This is a mixture that is not uniform in composition. Its components can easily be separated from one another. For example, pile of soil is a heterogeneous mixture because it consists of different components.</span>

8 0

3 years ago

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