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hodyreva [135]
3 years ago
12

Explain how this increases their efficiency. Explain how this increases their efficiency. Antireflective coating causes the phas

e shift of the light on the interface between the air and the panel increasing the path length of the light, so the solar panel turn more light into the energy. Antireflective coating decreases the index of refraction of the solar panel, so the losses of light caused by the refraction in the panel decreases, and the efficiency of the panel increases. Antireflective coating cancels the reflection of light from the panel, so the greater part of light enters the solar panel and can be turned into the energy. Antireflective coating refracts the light falling on the panel so the light of different wavelengths falls onto the different places of the solar panel and turns into energy with increased efficiency.
Physics
1 answer:
sweet [91]3 years ago
7 0

Answer:

c) True. If the coating cancels the light requested by the reflection, so there is more energy to enter the cell and therefore its efficiency increases

Explanation:

This exercise asks to analyze the effect of the antireflective coating on the efficiency of solar cells.

Let's start by expressing the expression for the interference of two light beams taken at when

* the phase change introduced when passing from air to 180º film

* the wavelength change by the refractive index of the film ln = lo / n

therefore the expression for destructive interference is

            2 n t = m λ

where m is an integer

with these concepts we can analyze the different statements

a) False. Phase shift does not change the wavelength of light

b) False. The refractive index of the solar cell is not affected by the refractive index of the film since the two materials do not mix.

c) True. If the coating cancels the light requested by the reflection, so there is more energy to enter the cell and therefore its efficiency increases

d) false. In solar cells the incidence is almost normal, therefore the effect of refraction (separation of colors for different angles) is very small

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The weight of the heart of a cow whose weight is 1518 lbs. Answer in units of lbs.
valina [46]

Answer:

Weight of cow = 7.59 lbs

Explanation:

Given:

Weight of cow = 1518 lbs

Find:

Weight of heart of a cow

Computation:

Note: It is not given that in the mammals the weight of heart is approximately 0.5% of total body weight

Weight of heart of a cow = [Weight of cow][0.5%]

Weight of cow = [1518][0.5%]

Weight of cow = 7.59 lbs

5 0
3 years ago
Suppose you are helping Galileo measure the acceleration due to gravity by dropping a canon ball from the tower of Pisa, You mea
Anni [7]

It is given that the height of the tower is

h=183 ft.

The uncertainty the measurement of this height is

\Delta h=0.2 ft

Drop time is measured as:

t=3.5s

The uncertainty in measurement of time is:

\Delta t=0.5 s

Using the equation of motion: h=ut+\frac{1}{2} at^2 where, h is the distance covered, u is the initial velocity, a is the acceleration and t is the time.

u=0 (because canon ball is in free fall). we need to calculate the value of a=g.

\Rightarrow h=\frac{1}{2}gt^2

\Rightarrow g=\frac{2h}{t^2}\\ \Rightarrow g=\frac{2\times 183ft}{(3.5s)^2}=29.87 ft/s^2

The uncertainty in this value is given by:

\Delta g=g\sqrt{(\frac{\Delta h}{h})^2+(\frac{2\Delta t}{t})^2}

Substitute the values:

\Delta g=29.87\sqrt{(\frac{0.2 }{183})^2+(\frac{2\times 0.5}{3.5})^2}=29.87\sqrt{1.19\times 10^{-6}+0.08}=29.87\times \sqrt{0.08}=29.87\times 0.28=8.44 ft/s^2



5 0
4 years ago
"The drawing shows three layers of different materials, with air above and below the layers. The interfaces between the layers a
My name is Ann [436]

Answer:

Angle of incidence that entered material b= 63.1°

Angle of incidence between a and b = 55.9°

Explanation: Using the formular:

n1sintheta1= n2sintheta2

The light ray which enters material B will be

1.4Sin72.8° = 1.5Sin theta

1.3373= 1.5Sintheta

sintheta = 1.3373/1.5

Sin^-1 0.8916 = Theta

63.1 = theta

When the ray hits interface with material a

1.5Sin63.1 = 1.3 Sin theta

1.3374 = 1.3Sin theta

Sintheta= 1.3374/1.3

Sin theta = 1.0877

There will be total reflection off the boundary b c because sin theta exceeded 1 in value.

The equation should be

1.4sin63.1 = 1.4 sin theta

Sin theta=72.8°

When the ray hits air-c boundary:

1.4sin72.8=1.00sin theta

Sin theta=1.3374/1 =1.3374

There is total reflection.

In material a,the ray will:

1.3sin72.8° = 1.00sin theta

There will be total reflection when the ray hits a-b boundary.

1.3sin72.8= 1.5sintheta

Sin theta= 1.2419/ 1.5

Sin theta =0.8279

Theta= Sin^-10.8279= 55.88°

When ray hits c-air boundary

1.4sin63.1= 1.00sintheta

1.2485= sin theta = Toal reflection.

Therefore when the ray of light pass through the layers of material a, b and c the boundary with air on top and bottom will be total reflection.

7 0
4 years ago
How can wind change landforms
slamgirl [31]
Well, wind can change landforms by storms, and hurricains, or other things that contain air...
~~~~~~~~~~~~~
Like, over a period of time... Wind can make landforms decrease in size, by weathering.
~~~~~~~~~~~~~~
Hope this helps! :)
5 0
3 years ago
Read 2 more answers
On which objects does gravity act?
Butoxors [25]

Answer:

all objects in the universe.

3 0
3 years ago
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