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avanturin [10]
3 years ago
10

Which strategies help build motivation?

Physics
1 answer:
Dmitrij [34]3 years ago
3 0

Answer:

t

Explanation:

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PLEASE HELP ME
pogonyaev

Answer:

The answer is Insulator, Conductor

Explanation:

A/An Insulator is a material in which charges will not move easily, whereas a/an Conductor is a material that allows charges to move about easily

5 0
2 years ago
Two airplanes leave an airport at the same time.The velocity of the first airplane is 700 m/h at a heading of 31.3 the velocity
MArishka [77]

Here in order to find out the distance between two planes after 3 hours can be calculated by the concept of relative velocity

v_{12} = v_1 - v_2

here

speed of first plane is 700 mi/h at 31.3 degree

v_1 = 700 cos31.3\hat i + 700 sin31.3\hat j

v_1 = 598.12\hat i + 363.7\hat j

speed of second plane is 570 mi/h at 134 degree

v_2 = 570 cos134 \hat i + 570 sin134 \hat j

v_2 = -396\hat i + 410\hat j

now the relative velocity is given as

v_{12} = (598.12 + 396)\hat i + (363.7 - 410)\hat j

v_{12} =994.12\hat i -46.3 \hat j

now the distance between them is given as

d = v* t

d = (994.12 \hat i - 46.3 \hat j)* 3

d = 2982.36\hat i - 138.9\hat j

so the magnitude of the distance is given as

d = \sqrt{2982.36^2 + 138.9^2}

d = 2985.6 miles

so the distance between them is 2985.6 miles

5 0
3 years ago
Read 2 more answers
What is the velocity of a car if it travels east 340 meters in 10 seconds? V = d/t
Nadya [2.5K]

Answer:

The awnser is d

Explanation:

i know cause i took the test

6 0
3 years ago
Read 2 more answers
If a car traveling at 60 km/h will skid 20m when its brakes lock, how far will it skid if it's traveling at 120 km/h when it's b
pantera1 [17]
<span>If a mouse and an elephant both run with the same kinetic energy, can you say ... 3. if a car traveling at60 km/h will skid 20 m when its brakes lock, how far will it skid if it is traveling at 120 km/h when its brakes lock? (This question is typical on ...</span><span>just get this and figure it out and this is your answer </span>
7 0
3 years ago
Two charges, X and Y, are placed along the x-axis. Charge X is +18 nC and is placed at x = 0. Charge Y is placed at a location o
Helen [10]

Answer:

Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m.

Explanation:

The Coulomb force between two charges, Q_1 and Q_2, separated by a distance, d, is given

F = k\dfrac{Q_1Q_2}{r^2}

<em>k</em> is a constant.

For the charge Z to be at equilibrium, the force exerted on it by charge X must be equal and opposite to the force exerted on it by charge Y.

It is to be placed along the <em>x</em>-axis. Hence, it is on the same line as charges X and Y.

Let the charge on Z be <em>Q</em>. It is positive.

Let the distance from charge X be <em>x m.</em> Then the distance from charge Y will be (0.60 - <em>x</em>) m.

Force due to charge X

F_X = k\dfrac{18Q}{x^2}

Force due to charge Y

F_Y = k\dfrac{-27Q}{(0.60-x)^2}

Since both forces are equal and opposite,

F_X = -F_Y

k\dfrac{18Q}{x^2} = -k\dfrac{-27Q}{(0.60-x)^2}

\dfrac{2}{x^2} = \dfrac{3}{(0.60-x)^2}

2(0.60-x)^2 = 3x^2

2(0.36-1.20x+x^2) = 3x^2

0.72-2.40x+2x^2 = 3x^2

x^2+2.40x-0.72 = 0

Applying the quadratic formula,

x = \dfrac{-2.40\pm\sqrt{2.40^2 - (4)(1)(-0.72)}}{2} = \dfrac{-2.40\pm\sqrt{8.64}}{2}

x = -2.7 or x = 0.27

Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m

3 0
3 years ago
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