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Alexus [3.1K]
3 years ago
13

How to find the measure of yz

Mathematics
1 answer:
stira [4]3 years ago
4 0
Use the Law of Sines (sina/A=sinb/B=sinc/C for any triangle)

YZ/sin30=50/sin90

YZ=50sin30   (sin90=1 :P)

YZ=25m

Use the 30,60,90° triangle ratios 1, √3, 2

YZ/1=50/2

YZ=25m

Using the Pythagorean Theorem....

(2*25)^2=YZ^2+(√3*YZ)^2

2500=YZ^2+3YZ^2

2500=4YZ^2

625=YZ^2

25m=YZ
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Answer:

This could easily be answered with a culculator but the answer is 20.

Step-by-step explanation:

5x4=20

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3 years ago
Jonah’s Restaurant reports net income of $20,000 during the year 2015. It distributes a dividend of $6,000 to its shareholders.
AlekseyPX
Retention ratio = (net income - dividends) / net income

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3 years ago
Estimate the area under the graph of f(x) = 2 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right and lef
I am Lyosha [343]
So hmm notice the picture below

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those rectangles are 0.39 radian long, since if you split π/2 in 4 pieces, you get around that much, the last rectangle there is a bit smaller than 0.39.... but they don't have to be 4 rectangles of equal length

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7 0
3 years ago
The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi
inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.        

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

\displaystyle\frac{dr}{dt} = -7\text{ inch per second}

The volume is decreasing at a constant rate.

\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

V = \displaystyle\frac{1}{3}\pi r^2 h

Instant volume =

525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}

Differentiating with respect to t,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)

Putting all the values, we get,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0
3 years ago
What is the volume of shed B?
skelet666 [1.2K]
Both the length and width of shed A are 6 feet.
I multiplied 6 by 2 and got 12.
My new equation is 12 × 12 × 8....

Which is 1,152. The answer is H.
4 0
3 years ago
Read 2 more answers
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