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Archy [21]
4 years ago
15

In 1990, California switched from a 6/49 lottery to a 6/53 lottery. Later, the state switched again to a 6/51 lottery. (a) Find

the probability of winning first prize in a 6/49 lottery. (b) Find the probability of winning first prize in a 6/53 lottery. (c) Find the probability of winning first prize in a 6/51 lottery. (d) How much more probable is it that one will win the 6/49 lottery than the 6/53 lottery? (Round your answer to the nearest whole number.)
Mathematics
1 answer:
zalisa [80]4 years ago
8 0

Answer:

(a) 9.9321*10^{-11}

(b) 6.0498*10^{-11}

(c) 7.7120^{-11}

(d) 1.6417 times more probable

Step-by-step explanation:

(a) The probability of winning a 6/49 lottery is given by:

P = \frac{1}{49*48*47*46*45*44} =9.9321*10^{-11}

(b) The probability of winning a 6/53 lottery is given by:

P = \frac{1}{53*52*51*50*49*48} =6.0498*10^{-11}

(c) The probability of winning a 6/51 lottery is given by:

P = \frac{1}{51*50*49*48*47*46} =7.7120^{-11}

(d) The ratio between the probabilities of winning the 6/49 lottery and winning the 6/53 lottery is:

r=\frac{9.9321*10^{-11}}{6.0498^{-11}}\\r=1.6417

It is 1.6417 times more probable.

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The question is incomplete. The complete question is :

Georgia has some 4-inch cubes like the one shown below. Georgia will put the cubes in the box shown below. What is the total number of cubes that Georgia needs to exactly cover the bottom of the box with a layer one cube deep?

Solution :

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