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Mazyrski [523]
3 years ago
13

How many Real solutions

Mathematics
2 answers:
Lisa [10]3 years ago
8 0

Answer:

A. 2 real roots:  (2, 7) and (1, 4).

Step-by-step explanation:

y = x^2 + 3

y = 3x + 1

So equating the right sides:

x^2 + 3 = 3x + 1

x^2 - 3x  + 2 = 0

(x - 2)(x - 1) = 0

So there are 2 roots.

They are x = 2 , y = 3(2) + 1 = 7 and

x = 1, y = 3(1) +1 = 4.

larisa [96]3 years ago
8 0
The right answer for this would be A
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