Answer: ![x \le 120](https://tex.z-dn.net/?f=x%20%5Cle%20120)
Multiply both sides by -6 to undo the operation of "division of -6" that is happening to x. This will isolate x and lead to the answer. Keep in mind that multiplying both sides by a negative number will flip the inequality sign.
The left pile has more because if you the 6 is added there and pluses all the 12 makes it a greater number
Factor the following:
12 x^4 - 42 x^3 - 90 x^2
Factor 6 x^2 out of 12 x^4 - 42 x^3 - 90 x^2:
6 x^2 (2 x^2 - 7 x - 15)
Factor the quadratic 2 x^2 - 7 x - 15. The coefficient of x^2 is 2 and the constant term is -15. The product of 2 and -15 is -30. The factors of -30 which sum to -7 are 3 and -10. So 2 x^2 - 7 x - 15 = 2 x^2 - 10 x + 3 x - 15 = x (2 x + 3) - 5 (2 x + 3):
6 x^2 x (2 x + 3) - 5 (2 x + 3)
Factor 2 x + 3 from x (2 x + 3) - 5 (2 x + 3):
Answer: 6 x^2 (2 x + 3) (x - 5)
There are multiple ways:
1) I would give you a 20 cent coin five times.
2)I would give you 10 dimes
3)I would give you 20 nickels
4)I would give you 5 dimes and 10 nickels
5)I would give you 10 nickels, a 20 cent and 2 dimes
6)I would give you 2 dimes, two 20 cent coins, and eight nickels
Those are a few I could think of atm. Let me know if you need some more.
Hope this helped :)