Answer:
false
Step-by-step explanation:
If scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points, then the minimum score you would need to be in the top 2% is equal to 88.929.
A problem of this type in mathematics can be characterized as a normal distribution problem. We can use the z-score to solve it by using the formula;
Z = x - μ / σ
In this formula the standard score is represented by Z, the observed value is represented by x, the mean is represented by μ, and the standard deviation is represented by σ.
The p-value can be used to determine the z-score with the help of a standard table.
As we have to find the minimum score to be in the top 2%, p-value = 0.02
The z-score that is found to correspond with this p-value of 0.02 in the standard table is 2.054
Therefore,
2.054 = x - 76.4 ÷ 6.1
2.054 × 6.1 = x - 76.4
12.529 = x - 76.4
12.529 + 76.4 = x
x = 88.929
Hence 88.929 is calculated to be the lowest score required to be in the top 2%.
To learn more about normal distribution, click here:
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Answer:
52.38%
Step-by-step explanation:
Given that,
Total number of students in the class is 42
Out of 42, 10 like hamburgers, 22 like pizza, 8 like french fries, and 2 like salad.
We need to find the percentage of the class chose pizza. There are 22 student who like to have pizza. Required percentage is given by :
So, 52.38% of students chose pizza.
Answer:
you need to be more specific like which ones are x or y
Step-by-step explanation:
ask it again or comment the specifics
