Tell whether each table represents a linear relationship...

A square wall is covered with sqare tiles. There are 85 tiles altogether along the two diagonals. How many tiles are there on th

olchik [2.2K]

Answer:

There are 1849 tiles on the whole wall.

Step-by-step explanation:

If there are 85 tiles along the two diagonals, we can use the following rule:

$\frac{85+1}{2}=43$

So we have 43 tiles in the first diagonal and 85-43 = 42 in the second diagonal.

Now, as we have a square the side will have 43 tiles so the total area will be cover with:

$A=43*43=1849$

Therefore, there are 1849 tiles on the whole wall.

I hope it helps you!

4 0

3 years ago

HELP PLEASE!! <3 <br> A rectangle has vertices (w,v), (w,z), and (z,z). Find the fourth vertex.

Vaselesa [24]

Answer:

Hey, Try practiceing on your own

Step-by-step explanation:

8 0

3 years ago

Which is a measure of the efficiency of an investment?

DiKsa [7]

Answer:

The correct answer is option B. Return on Investment.

Step-by-step explanation:

The return on investment is used when we want to measure the capacity of an investment, or compare it among several other investments.

Here the <u>benefit of a certain investment will be compared in contrast to the money invested. </u>

To calculate the return on investment there is a formula which will give us a percentage:

ROI = Margin on sales X asset turnover.

Now let's clarify what each of these things is:

Margin on sales: it is the result obtained from the calculation of benefits / sales.

Asset Rotation: this is the result obtained from the calculation of Average Total Sales / Assets.

7 0

3 years ago

Read 2 more answers

Can someone pleaseeee help and if you’re correct I’ll give u brainlist! Yes or no?

Softa [21]

Answer:

yes

Step-by-step explanation:

6 0

3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

so

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago