3 years ago

What is the most precise name for quadrilateral ABCD with vertices A(-2,4) B(5,6) C(12,4) D(5,2)

1 answer:

7 0

I graphed it (and I hoped I did that correctly).
It doesn't seem as if it would have any specific name.

You might be interested in

lorasvet [3.4K]

Answer:13

Step-by-step explanation:

13^2

6 0

3 years ago

loris [4]

Answer:

The Jacobys drove 19 1/2 hours from Monday to Thursday.

7 0

3 years ago

MrMuchimi

Answer:144

Step-by-step explanation:

7 0

4 years ago

balandron [24]

Answer:

The first step is to determine the average

$x= \frac{0,6+0,7+ 0,7+0,3+0,4+ 0,5+ 0,4 +0,2}{8}\\\ x= 0,475$

The exercise says it’s a normal distribution: (n=8)

$s^{2}= \frac{1}{n-1} ((0,6.x)^2+2(0,7-x)^2+(0.3-x)^2+2(0.4-x)^2+(0.5-x)^2+(0.2-x)^2)\\\ \frac{1}{7}*0,235 = 0,0336 \\\\ s= 0183$

According to the exercise, the mean is equal to 0,5 then the value of t of the distribution can be obtained

$t= \frac{x-u}{\frac{s}{\sqrt{n} }}\\\ t= \frac{0,475 - 0,5}{0,183}\\\ t= -0,3860$

The variable t has 7 grade to liberty, we calculate the p-value as:

$2* P(t < - 0,3860)= \\\ 2* 0,3554 = 0,7108$

This value is very high, therefore the hypothesis is not rejected

7 0

4 years ago

Rus_ich [418]

Answer: -1/3

Step-by-step explanation:

correct me if im wrong

8 0

3 years ago