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3 years ago

How do you sovle simple equations

Mathematics

1 answer:

kicyunya [14]3 years ago

7 0

Answer:

When solving a simple equation, think of the equation as a balance, with the equals sign (=) being the fulcrum or center. Thus, if you do something to one side of the equation, you must do the same thing to the other side. Doing the same thing to both sides of the equation (say, adding 3 to each side) keeps the equation balanced.

Solving an equation is the process of getting what you're looking for, or solving for, on one side of the equals sign and everything else on the other side. You're really sorting information. If you're solving for x, you must getx on one side by itself.

Addition and subtraction equations

Some equations involve only addition and/or subtraction.

Example 1

Solve for x.

x + 8 = 12

To solve the equation x + 8 = 12, you must get x by itself on one side. Therefore, subtract 8 from both sides.

equation

To check your answer, simply plug your answer into the equation:

equation

Step-by-step explanation:

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Solve for x. x5x+15=1x+3 no solution −3 and 5 −3 5

Andrei [34K]

Answer:

-3

Step-by-step explanation:

5x + 15 = 1x + 3

Add -1x and -15 on both sides.

5x - 1x = 3 - 15

4x = -12

Divide 4 into both sides.

4x/4 = -12/4

x = -3

The solution for the equation is x = -3.

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3 years ago

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ludmilkaskok [199]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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3 years ago

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3 years ago

Determine if the matrix below is invertible. Use as few calculations as possible. Justify your answer.

Marysya12 [62]

Answer:

This shows 3 pivot position matrixes.

Step-by-step explanation:

The given matrix is:

$\left[\begin{array}{ccc}1&-2&-5\\0&4&3\\-3&3&0\end{array}\right]$

The option D is correct for this matrix.

The matrix is invertible and the given matrix has 3 pivot positions.

The matrix is invertible if its determinant is nonzero.

Multiply the 3rd row by 1/3.we get:

$\left[\begin{array}{ccc}1&-2&-5\\0&4&3\\-1&1&0\end{array}\right]$

Now, add the first row with third row:

$\left[\begin{array}{ccc}0&-1&-5\\0&4&3\\-1&1&0\end{array}\right]$

Replace third row by first row:

$\left[\begin{array}{ccc}-1&1&0\\0&4&3\\0&-1&-5\end{array}\right]$

This shows 3 pivot position matrixes.

Hence, a matrix is invertible and has 3 pivot positions.

7 0

3 years ago