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Answer:
Step-by-step explanation:
A parallel line will have the same slope as the reference line. In this case, I don't see the "given line" as promised in the question. If it does appear, and it looks like y = 5x + 3, for example, the slope is 5 and the new line will have the same slope.
<h3><u>If this slope is correct</u>, we can start the equation for the parallel line that goes through point (-3,2) by starting with:</h3><h3 /><h3>y = 5x + b</h3><h3 /><h3>We need a value of b that forces the line to go through point (-3,2). We can do that by using the given point in the equation and solving for b:</h3><h3>y = 5x + b</h3><h3>2 = 5(-3) + b</h3><h3>b = 17</h3><h3 /><h3>The parallel line to y=5x+3 is</h3><h3>y = 5x + 17</h3><h3 /><h3>See attachment.</h3><h3 /><h3 /><h3 />
By applying the knowledge of similar triangles, the lengths of AE and AB are:
a.
b.
<em>See the image in the attachment for the referred diagram.</em>
<em />
- The two triangles, triangle AEC and triangle BDC are similar triangles.
- Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.
<em>This implies that</em>:
- AC/BC = EC/DC = AE/DB
<em><u>Given:</u></em>
<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>
EC/DC = AE/DB
- Plug in the values
- Cross multiply
- Divide both sides by 5.4
<u>b. </u><u>Find the length of </u><u>AB:</u>
AC = 6.15 cm
To find BC, use AC/BC = EC/DC.
- Plug in the values
- Cross multiply
- Thus:
- Substitute
Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:
a.
b.
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