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3 years ago

What's the diff between the x & y intercepts? I sorta know it

Mathematics

2 answers:

Nat2105 [25]3 years ago

8 0

X goes in the horizontal (Left to Right) and Y goes vertical (North to South

inna [77]3 years ago

5 0

Not all functions will have intercepts, but when you are working with the graph of a linear function, it will have both an x-intercept and a y-intercept. An x-intercept is where the graph crosses the x-axis and a y-intercept is where it crosses the y-axis. Let's think about a line that crosses the x-axis.

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it takes 3 buckets of water to fill 1/3 of a fish tank. how many buckets are needed to fill yhe whole tank

maxonik [38]

9 because it take 3 to fill 1/3 do 3 times 3 and its nine

7 0

2 years ago

A bank advertises an interest rate of 4% per year, compounded monthly

Darina [25.2K]

Given :

Interest rate , r = 4 %.

To Find :

The APY .

Solution :

APY is given by :

$APY=(1+\dfrac{r}{n})^n-1$

Here , r is compound interest and n is number of time compounded .

So ,

$APY=(1+\dfrac{r}{n})^n-1\\\\APY=(1+\dfrac{4}{12})^{12}-1\\\\APY=30.57\%$

Therefore , APY is 30.57 % .

Hence , this is the required solution .

4 0

3 years ago

If $1600 earned simple interest of $56.24 in 2 months, what was the simple interest rate? The simple interest rate is % (Do not

Fiesta28 [93]

Answer:

$\$21.1$

Step-by-step explanation:

We know that for principal amount P , time period T and rate of interest $R\%$ , simple interest is given by $S.I. = \frac{P\times R\times T}{100}$ .

Here ,

$P=\$1600\\T=2\,\,months=\frac{2}{12}\,\,years=\frac{1}{6}\,\,years\\S.I=\$56.24$

To find : simple interest rate i.e., $R\%$

On putting values of $P\,,\,T\,,\,S.I$ in formula , we get $S.I. = \frac{P\times R\times T}{100}$

$56.24 = \frac{1600\times R\times 1}{600}\\R=\frac{56.24\times 600 }{1600}=\frac{703\times 3}{100}=\$21.09$

Now we need to round off the answer to the nearest tenth .

So, simple interest rate is % = $\$21.09$ = $\$21.1$

8 0

2 years ago

What is the tan invers of 3i/-1-i

postnew [5]

z = 3i / (-1 - i )

z = 3i / (-1 - i ) × (-1 + i ) / (-1 + i )

z = (3i × (-1 + i )) / ((-1)² - i ²)

z = (-3i + 3i ²) / ((-1)² - i ²)

z = (-3 - 3i ) / (1 - (-1))

z = (-3 - 3i ) / 2

Note that this number lies in the third quadrant of the complex plane, where both Re(z) and Im(z) are negative. But arctan only returns angles between -π/2 and π/2. So we have

arg(z) = arctan((-3/2)/(-3/2)) - π

arg(z) = arctan(1) - π

arg(z) = π/4 - π

arg(z) = -3π/4

where I'm taking arg(z) to have a range of -π < arg(z) ≤ π.

6 0

2 years ago

Solve the equation v² = 24

drek231 [11]

Answer:

v=6

v=−4

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers