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Ulleksa [173]
3 years ago
6

Perform the operations, multiply, and simplify.-a^3b (3a^2 b^5 - ab^4 - 7a ^2 b.

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0
I hope this helps you



3a^5.b^6-a^4.b^5-7a^5.b
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ICE Princess25 [194]

Answer:

7x² + 5x

Dtep-by-step explanation:

(9x² + 8x) - (2x² + 3x)

9x² + 8x - 2x²- 3x

7x² + 5x

3 0
3 years ago
What is 45% of 78? Plaese help or else idk i just needed to type more.
zepelin [54]
78×45/100
=35.1. As a result, 35.1 is 45% of 78. Hope it help!
3 0
3 years ago
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Do I need to put parentheses in this? Why it why not?
Oksana_A [137]

Answer:

Parentheses can change the result of the answer. If you want to add 4 and 0.95 first, then multiply that number by 3, then you need parentheses.

Step-by-step explanation:

When you are given the question 3 X 4 + 0.95, it has to types of operations. <u>People solve using the order PEDMAS</u>:

Parentheses,

Exponents,

Division and Multiplication,

Addition and Subtraction.

Since there are <u>no parentheses</u> or exponents, the solver will do multiplication first, then addition.

3 X 4 + 0.95     Multiply first

= 12 + 0.95       Now add

= 12.95         Answer without parentheses

If you add <u>parentheses around 4 + 0.95</u>, the answer would change. According to PEDMAS, the parentheses must be solved before anything else.

3 X (4 + 0.95)       Add inside parentheses

= 3 X (4.95)       Now multiply

= 14.85           Answer with parentheses

If you added <u>parentheses around 3 X 4</u>, the answer would not change, because you still multiply first.

(3 X 4) + 0.95      Solving parentheses first

= 12 + 0.95       Add

= 12.95          Answer same as original

3 0
3 years ago
The amounts of food waste generated in a region during two years were 37,500,000 tons and 30,400,000 tons. What was the total fo
alex41 [277]

Answer:

6.79 ⋅ 107

Step-by-step explanation:

3 0
2 years ago
The solution to this system of equations lies between the x-values -2 and -1.5. At which x-value are the two equations approxima
drek231 [11]
Hello,
\left \{ {{y= \dfrac{1}{x+2} } \atop {y=x^2+2}} \right. \\\\&#10;&#10; \left \{ {{y= \dfrac{1}{x+2} } \atop {\dfrac{1}{x+2}=x^2+2}} \right. \\\\&#10;&#10; \left \{ {{y= \dfrac{1}{x+2} } \atop {x+2= \dfrac{1}{x^2+2} }} \right. \\\\&#10;&#10; \left \{ {{y= \dfrac{1}{x+2} } \atop {x= \dfrac{1}{x^2+2} -2}} \right. \\\\&#10;&#10;&#10;
x=-1.81053571 and y=<span> 5,27803957 </span>

Download xls
3 0
3 years ago
Read 2 more answers
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