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Sergeu [11.5K]
3 years ago
15

How to solve this!! Please!

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

k^2 -3k +9/2

(k-3/2)^2

Step-by-step explanation:

k^2 -3k

Take b/2 and then square it to find the term to complete the square

(-3/2) ^2 = 9/4

k^2 -3k +9/2

The expression factors to (k-b/2)^2

(k-3/2)^2

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Suppose you own 1 stock of Amazon and it cost $750 to buy it. After you buy the stock, it increases by 100%.
viva [34]

Answer:

1500

Step-by-step explanation:

750+750

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Which statement describes whether a right triangle can be formed using one side length from each of these squares?
balu736 [363]

Answer:

Step-by-step explanation:

The area of the given squares are

Area = 64 in

Area = 225 in

Area = 289 in

The length of each side of a square is determined by finding the square root of its area. For the first square, the length of its side is √64 = 8inches. For the second square, the length of its side is √225 = 15inches. For the third square, the length of its side is √289 = 17inches.

For a right angle triangle to be formed, Pythagorean theorem must be obeyed. Sum of the square of the smaller sides must equal the square of the longer side. Therefore,

8² + 15² = 17²

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Therefore, the correct statement is

Yes, a right triangle can be formed because the sum of the areas of the two smaller squares equals the area of the largest square

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6791 of per year answer
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Answer:

<u>Given function</u>

  • h(x) = 2x - 1

#15 Find the inverse of h(x)

<u>Substitute x with y and h(x) with x and solve for y:</u>

  • x = 2y - 1
  • 2y = x + 1
  • y = 1/2x + 1/2

<u>The inverse is:</u>

  • h⁻¹(x) = 1/2x + 1/2

#16 The graph with both lines is attached.

The x- and y-intercepts of both functions have reversed values.

#17 Table of the inverse function  will contain same numbers with swapped domain and range.

<u>Initial look is like this:</u>

  • <u>x        |  -3  |  -2  | -1  |  0  |    1  |  2  | 3</u>
  • h⁻¹(x)  |  -1   |       | 0   |      |    1  |      | 2

<u>The rest of the table is filled in by finding the values:</u>

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