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Dafna1 [17]
3 years ago
13

joe worked 8 hours on Monday. If he worked 40 hours in the week what is the fraction of the total time worked on monday

Mathematics
1 answer:
maria [59]3 years ago
6 0
Joe worked 8/40 or 1/5 of that time on Monday.
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Find the value of the expression.<br> c²b<br> for b = 5 and c = 3
kicyunya [14]

Answer:

45

Step-by-step explanation:

c^2*b

We know that c is 3, and b is 5, so we can substitute them in

3^2*5

Solve the exponent first

9*5

Multiply

45

7 0
3 years ago
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the area of the vegetable garden is 0.4 of the area of the community garden. What is the area of the vegetable garden?
labwork [276]

Answer:

11:6

Step-by-step explanation:

I did the test brainly me

8 0
3 years ago
6. In a standard deck of cards:
Dafna11 [192]

Events A and B are dependent (option B).

<h3>What are dependent events?</h3>

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7 0
2 years ago
What is the answer to this problem?<br>7-3x - 15=19
sergij07 [2.7K]
The answer is x = -9
6 0
3 years ago
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To evaluate log2(3), Autumn reasoned that since log2(2) = 1 and log2(4) = 2, log2(3) must be the average of 1 and 2 and therefor
geniusboy [140]

Answer:

log₂(3) = 1.585 ≠ 1.5

Her thinking is not valid because the technique of average is valid only  if the graph of the function is a straight line, but the graph of the log function is not a straight line.

Therefore the values cannot be taken by average

Step-by-step explanation:

Given:

log₂(2) = 1

log₂(4) = 2

To evaluate :  log₂(3)

Now,

we know that

logₓ(y) = \frac{\log(y)}{\log(x)}        (Here the log has same base in the numerator and the denominator i.e 10)

therefore,

log₂(3) =  \frac{\log(3)}{\log(2)}

also,

log(2) = 0.3010

log(3) = 0.4771

thus,

log₂(3) =  \frac{0.4771}{0.3010}

or

log₂(3) = 1.585 ≠ 1.5

Her thinking is not valid because the technique of average is valid only  if the graph of the function is a straight line, but the graph of the log function is not a straight line.

Therefore the values cannot be taken by average

7 0
3 years ago
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