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Dafna1 [17]
3 years ago
13

joe worked 8 hours on Monday. If he worked 40 hours in the week what is the fraction of the total time worked on monday

Mathematics
1 answer:
maria [59]3 years ago
6 0
Joe worked 8/40 or 1/5 of that time on Monday.
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Marianna [84]
The answer is (0,3)

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3 years ago
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What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)
Pachacha [2.7K]

Answer:

The third option listed: \sqrt[3]{2x} -6\sqrt[3]{x}\\

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

7\sqrt[3]{2x}  -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x}  -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x}  -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x}  -6\sqrt[3]{2x} -6\sqrt[3]{x}

And now we combine all like terms (notice that the only two terms we can combine are the first two, which contain the exact same radical form:

7\sqrt[3]{2x}  -6\sqrt[3]{2x} -6\sqrt[3]{x}=\\=\sqrt[3]{2x} -6\sqrt[3]{x}

Therefore this is the simplified radical expression: \sqrt[3]{2x} -6\sqrt[3]{x}\\

5 0
3 years ago
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Phantasy [73]

Answer:

ΔABC≅ΔDEC by AAS

Step-by-step explanation:

You can use the AAS method of congruency.

Since you already have <BAC and <EDC congruent to eachother, and sides BC and EC congruent to each other, you only need that one remaining angle in between. <ACB can be proven congruent to <DCE by the Vertical Angles Theorem, and that gives you the AAS you need to prove that these two triangles are congruent

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2 years ago
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Answer:

192 square meters

Step-by-step explanation:

Imma assume her phones a rectangle, so you're gonna length times width

L x W = area

12 x 16 = area

192 = area

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iogann1982 [59]

Answer:

the median marks the middle or the mid-point of the data and is often shown by the line that divides the box into two parts.

Step-by-step explanation:

hope this helps:)

6 0
3 years ago
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