All categories

3 years ago

-23 + (-11) - (-15) + 21

Mathematics

1 answer:

svlad2 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

(-23 - 11) + (15 + 21)

-34 + 36

36 - 34

You might be interested in

A group of 625 students has a mean age of 15.8 years with a standard deviation of 0.6 years. The ages are normally distributed.

Tom [10]

16.2-15.8/0.6=0.6667. Use normalcdf() to find the percentage from -999 to 0.6777 which is 0.7476*625=467

7 0

3 years ago

Austin takes 1 minute and 45 seconds to run three-quarters of a circular track. His rate of motion is /

castortr0y [4]

Length of circular track is:

L = 2*r*pi

He run 3/4 of it so length is:
L' = 3*2/4*r*pi = 3/2*r*pi

To calculate speed of his movement we use formula:
v = s/t where s = L' and t = 1 minute 45 seconds = 105 seconds

v = L'/t = 3*r*pi/2*105

v = r* pi/70

If we take that r = 1

answer
$\pi /70$

6 0

3 years ago

Please answer this correctly

SCORPION-xisa [38]

Answer:

1. <B, <A, <C

2. <E, <D, <F

Step-by-step explanation:

Recall: the longest side of a triangle would be opposite the largest angle, while the shortest side of a triangle would be opposite the smallest angle.

1. <B is opposite the shortest side, 3 (smallest angle)

<A is opposite the medium side, 4 (medium angle)

<C is opposite to the largest side, 5 (largest angle)

Therefore, the angles in ascending order would be:

<B, <A, <C

2. <E is opposite the shortest side, 5 (smallest angle)

<D is opposite the medium side, 6 (medium angle)

<F is opposite to the largest side, 7 (largest angle)

Therefore, the angles in ascending order would be:

<E, <D, <F

6 0

3 years ago

In the figure below, AB=AE, AC=AD and AP is perpendicular to BE. Prove that BC=DE.

NISA [10]

Step-by-step explanation:

1) In the figure, as AB is equal to AE, ABE is an equilateral triangle.

As AP is perpendicular to BE

=> AP is the height of the triangle ABE.

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle.

=> P is the midpoint of BE

=> PE = PB

2) In the figure, as AC = AD, so that ACD is an equilateral triangle.

As AP is perpendicular to BE, so that it is perpendicular to CD as well

=> AP is the height of the triangle ACD

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle ACD.

=> P is the midpoint of CD

=> PC = PD

We have:

+) PB = PE

+) PC = PD

=> PB - PC = PE - PD => BC = DE

5 0

4 years ago

PLEASE HELP !! ILL GIVE 40 POINTS ; PLUS BRAINLIEST !! DONT SKIP ANSWER.

stiks02 [169]

POQ AND KLJ

They are the only alternate exterior angles

6 0

3 years ago

Read 2 more answers