A reasonable domain and range is the set of values that exist for the function. The sets that are not reasonable are not considered domain and range. For instance, f(x) = 15√(x - 3)
The reasonable domain is {x | R, x ≥ 3} since you can't have negative value inside the radicand.
The reasonable range is {f(x) | R, f(x) ≥ 0} since the minimum value is 0 [Noting that x = 3 gives f(3) = 15√(3 - 3) = 15√0 = 0]
Answer:
$45 (corrected answer)
Step-by-step explanation:
Given
Gavin : Jim = 1 : 3
fraction that Gavin gets = 1 / (1+3) = 1/4
fraction that Jim gets = 3 / (1+3) = 3/4
given that Gavin gets $15,
Gavin's share = (1/4) ----> equivalent to $15
Jim's share = (3/4) ----> equivalent to $15 x 3 = $45
To change a fraction to a decimal divide the numerator by the denominator. 6÷11=.5454545454545 ANSWER: .5454545454545
Answer:
f(1) ≈ 2.7864
Step-by-step explanation:
You appear to want a couple of iterations of ...
... y[n+1] = y[n] +arcsin(x[n]·y[n]}·(x[n+1] -x[n])
... x[n+1] = x[n] +0.5
... x[0] = 0
... y[0] = 2
Filling in the values, we get
... y[1] = 2 + arcsin(0·2)·0.5 = 2
... y[2] = 2 + arcsin(0.5·2)·0.5 = 2 +(π/2)·0.5 ≈ 2.7864 . . . . corresponds to x=1
