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Ronch [10]
2 years ago
6

What is the answer to (-2x-1)-(x-7)

Mathematics
1 answer:
Ray Of Light [21]2 years ago
6 0
(-2x-1)-(x-7)
-2x-x+7-1
-3x+6
-3x=-6
x=2
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What's the price of the pencil? I can't solve it without the price of the pencil.
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George and Lea each toss a tetrahedral die with faces numbered 1 through 4, and then multiply the two resulting numbers. If the
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Answer:

I think the total number of combinations of 3 from 6 = 6C3 = 20

All possible combinations of 3 which have a product divisible by 3 must contain either a 3 or a 6.

So the number not divisible must be 3 combinations from the number 1, 2, 4, and 5.= which is 4

So the required probability is 20-4 ? 20 = 16/20 = 0.8 Answer

Hope this help you! :)

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One month, the price of gas was $1.44. The next month the price of gas was $2.40. What was the approximate percent of increase f
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3 years ago
Which graph shows a linear function.<br> A) <br> B) <br> C) <br> D)
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Read 2 more answers
Can you please help me with 23 and 25 I do not understand!!! Please help
adell [148]

when you multiply a number by a value that's greater than 1, that number increases, for example 2 and then we multiply it like 2 * 3, clearly 2*3 is greater than 2.

now when you multiply a number  by a value that's lesser than 1, that number decreases, for example 2 and then we multiply it by something like 1/4, so 2 * 1/4 = 1/2, well, clearly 1/2 is smaller than 2, so 1/2 is a decreased value of 2.

23)

we have here 4/7, and then a product, well, the product is 4/7 and 9/10, however 9/10 is less than 1, recall 1 = 10/10, 9/10 is just a tiny bit less than 1.

because we're multiplying 4/7 by some amount less than 1, the product is a smaller value than 4/7, thus

 \bf \cfrac{4}{7}~~>~\left( \cfrac{9}{10}\times \cfrac{4}{7} \right)

25)

we have here 5/6 and we multiply it by 7/7, wait a minute!!! 7/7 = 1, we're really just multiplying 5/6 by 1 then, what does that give us?  well, 5/6 * 1  = 5/6, just the number itself,

\bf \cfrac{5}{6}~~=~\left( \cfrac{5}{6}\times \cfrac{7}{7} \right)

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2 years ago
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