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pychu [463]
2 years ago
14

Write an equation of each line in point-slope form. containing (2,1) and (3,4)

Mathematics
1 answer:
Leokris [45]2 years ago
7 0

Answer:

y=3x-5

Step-by-step explanation:

This is the only line that will pass through these points.

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What property can you use to write an equivalent expression for -5(x-2)? Explain.
emmainna [20.7K]

Answer:

-5x+10

Step-by-step explanation:

-5(x-2)=-5x+10

3 0
3 years ago
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What is the nonpermissible value of x in 5x/6x+3
cestrela7 [59]

Answer: -\frac{1}{2}

<u>Step-by-step explanation:</u>

\frac{5x}{6x+3}

Restriction: 6x + 3 ≠ 0     <em>denominator cannot be zero</em>

                   <u>     -3  </u>  <u> -3 </u>

                    6x      ≠ -3

                 <u> ÷6       </u>   <u>÷6 </u>

                      x       ≠ -\frac{1}{2}

4 0
3 years ago
How can you write the expression with rationalized denominator? sqrt3 - sqrt6 / sqrt 3 + sqrt 6
harina [27]
Answer:  2√2 - 3

Explanation:


The expession written properly is:

\frac{ \sqrt{3}- \sqrt{6}  }{ \sqrt{3}+ \sqrt{6} }

To rationalize that kind of expressions, this is to eliminate the radicals on the denominator you use conjugate rationalization.

That is, you have to multiply both numerator and denominator times the conjugate of the denominator.

The conjugate of √3+√6 is √3 - √6, so let's do it:

\frac{ \sqrt{3} - \sqrt{6} }{ \sqrt{3} + \sqrt{6} } . \frac{ \sqrt{3}- \sqrt{6}  }{ \sqrt{3}- \sqrt{6} }

To help you with the solution of that expression, I will show each part.

1) Numerator: (√3 - √6) . (√3 - √6) = (√3 - √6)^2 = (√3)^2 - 2√3√6 + (√6)^2 =

= 3 - 2√18 + 6 = 9 - 6√2.

2) Denominator: (√3 + √6).(√3 - √6) = (√3)^2 - (√6)^2 = 3 - 6 = - 3

3) Then the resulting expression is:

 9 - 6√2
-----------
 -3

Which can be further simplified, dividing by - 3

    -3 + 2√2

Answer: 2√2 - 3

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3 years ago
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Joey makes 20 less dollars than Jeremy. If they make a total of $72, how much does
svetoff [14.1K]

Answer:

Joey makes 52 dollars

Step-by-step explanation:

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How much is 1 watt in volts
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The answer to your is 100 volts

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