(2+4i) + (9+10i) = (2+9) + (4i+10i)

9=2+x <br><br> Please show work (:

Rudiy27

9=2+X

X=9-2

X=7

This is anwser!!!

8 0

3 years ago

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Mr. McGloughlin’s horses eat a total of 19 liters 2 deciliters of rolled oats, and drink a total of 46 liters 4 deciliters of wa

Hunter-Best [27]

Answer:

459.2 liters.

Step-by-step explanation:

Let us convert our given amount of rolled oats and water in deciliters.

1 liter = 10 deciliters

19 liters = 19*10 deciliters = 190 deciliters.

$\text{Total amount of rolled oats consumed per day}=(190+2)\text{ deciliters}$

$\text{Total amount of rolled oats consumed per day}=192\text{ deciliters}$

46 liters=46*10=460 deciliters

$\text{Total amount of water consumed per day}=(460+4)\text{ deciliters}$

$\text{Total amount of water consumed per day}=464\text{ deciliters}$

Now let us find weekly consumption of oats and water by multiplying daily consumption of both items by 7.

$\text{Total weekly consumption of oats and water}=7*(464+192)\text{ deciliters}$

$\text{Total weekly consumption of oats and water}=7*(656)\text{ deciliters}$

$\text{Total weekly consumption of oats and water}=4592\text{ deciliters}$

Let us convert weekly consumption of water and oats into liters.

$\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10\frac{\text{ deciliters}}{\text{liter}}}$

$\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10}\cdot\frac{\text{ liters}}{\text{ deciliters}}}$

$\text{Total weekly consumption of oats and water}=\frac{4592}{10}\text{ liters}$

$\text{Total weekly consumption of oats and water}=459.2\text{ liters}$

Therefore, total weekly combined consumption of oats and water is 459.2 liters.

5 0

3 years ago

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Helps asap please help

Novosadov [1.4K]

Yes because the line is curved

5 0

3 years ago

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5. What is angel 8 use picture above

Vikki [24]

Answer:

Angle 8 = Angle 4

Step-by-step explanation:

6 0

3 years ago

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A simple die is thrown 100 times and the number five appears 14 times. Find the experimental probability of throwing a five, giv

mario62 [17]

Answer:

The experimental probability of throwing a five is 0.087.

Step-by-step explanation:

Given:

Number of trials (n) = 100

Number of times 5 appears (x) = 14

Let the event of occurrence of 5 be success and the probability represented by 'p'. So, all the other numbers occurrence is failure and its probability is represented as 'q'.

Probability of success is given as:

$p=\frac{Number\ of\ favorable\ events}{Total\ number\ of\ outcomes}$

Favorable event is occurrence of 5. So, its number is 1 as there is only one 5 in the die. Total outcomes are 6 as there are six numbers. So,

$p=\frac{1}{6}$

Now, probability of failure is given by the formula:

$q=1-p=1-\frac{1}{6}=\frac{5}{6}$

Now in order to find the experimental probability of 14 successes out of 100 trials, we apply Bernoulli's theorem which is given as:

$P(x) = ^nC_xp^xq^{n-x}$

Plug in all the given values and find the probability of 14 successes. This gives,

$P(x=14)=^{100}C_{14}(\frac{1}{6})^{14}(\frac{5}{6})^{100-14}\\\\P(x=14)=0.087$

Therefore, the experimental probability of throwing a five is 0.087.

8 0

3 years ago