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Sedbober [7]
3 years ago
11

(2+4i) + (9+10i) = (2+9) + (4i+10i)

Mathematics
1 answer:
HACTEHA [7]3 years ago
5 0
11+14i=11+14

The answer is 0
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9=2+x <br><br> Please show work (:
Rudiy27

9=2+X

X=9-2

X=7

This is anwser!!!

8 0
3 years ago
Read 2 more answers
Mr. McGloughlin’s horses eat a total of 19 liters 2 deciliters of rolled oats, and drink a total of 46 liters 4 deciliters of wa
Hunter-Best [27]

Answer:

459.2 liters.

Step-by-step explanation:

Let us convert our given amount of rolled oats and water in deciliters.

1 liter = 10 deciliters

19 liters = 19*10 deciliters = 190 deciliters.

\text{Total amount of rolled oats consumed per day}=(190+2)\text{ deciliters}

\text{Total amount of rolled oats consumed per day}=192\text{ deciliters}

46 liters=46*10=460 deciliters

\text{Total amount of water consumed per day}=(460+4)\text{ deciliters}

\text{Total amount of water consumed per day}=464\text{ deciliters}

Now let us find weekly consumption of oats and water by multiplying daily consumption of both items by 7.

\text{Total weekly consumption of oats and water}=7*(464+192)\text{ deciliters}

\text{Total weekly consumption of oats and water}=7*(656)\text{ deciliters}  

\text{Total weekly consumption of oats and water}=4592\text{ deciliters}

Let us convert weekly consumption of water and oats into liters.

\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10\frac{\text{ deciliters}}{\text{liter}}}  

\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10}\cdot\frac{\text{ liters}}{\text{ deciliters}}}

\text{Total weekly consumption of oats and water}=\frac{4592}{10}\text{ liters}

\text{Total weekly consumption of oats and water}=459.2\text{ liters}

Therefore, total weekly combined consumption of oats and water is 459.2 liters.

5 0
3 years ago
Read 2 more answers
Helps asap please help
Novosadov [1.4K]
Yes because the line is curved
5 0
3 years ago
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5. What is angel 8 use picture above
Vikki [24]

Answer:

Angle 8 = Angle 4

Step-by-step explanation:

6 0
3 years ago
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A simple die is thrown 100 times and the number five appears 14 times. Find the experimental probability of throwing a five, giv
mario62 [17]

Answer:

The experimental probability of throwing a five is 0.087.

Step-by-step explanation:

Given:

Number of trials (n) = 100

Number of times 5 appears (x) = 14

Let the event of occurrence of 5 be success and the probability represented by 'p'. So, all the other numbers occurrence is failure and its probability is represented as 'q'.

Probability of success is given as:

p=\frac{Number\ of\ favorable\ events}{Total\ number\ of\ outcomes}

Favorable event is occurrence of 5. So, its number is 1 as there is only one 5 in the die. Total outcomes are 6 as there are six numbers. So,

p=\frac{1}{6}

Now, probability of failure is given by the formula:

q=1-p=1-\frac{1}{6}=\frac{5}{6}

Now in order to find the experimental probability of 14 successes out of 100 trials, we apply Bernoulli's theorem which is given as:

P(x) = ^nC_xp^xq^{n-x}

Plug in all the given values and find the probability of 14 successes. This gives,

P(x=14)=^{100}C_{14}(\frac{1}{6})^{14}(\frac{5}{6})^{100-14}\\\\P(x=14)=0.087

Therefore, the experimental probability of throwing a five is 0.087.

8 0
3 years ago
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