X^2+4x=-3
x^2+4x+3=0
(x+1)(x+3)=0
x+1=0 so x=-1
x+3=0 so x=-3
so the solution is x=-3,-1
Hope this helped! Please rate my answer if I helped you! Any questions please feel free to ask! Thank you so much!
You need to find points where the line g(x) intercepts the quadratic function f(x) in one and only one point.
Then 3x^2 + 4x -2 = mx - 5
solve 3x^2 + 4x - mx -2 + 5 = 0
3x^2 + (4 - m)x + 3 = 0
In order to there be only one solution (one intersection point) the radicand of the quadratic formula must be 0 =>
b^2 - 4ac = (4 - m)^2 - 4(3)(3) = 0
(4 - m)^2 = 24
4 - m = +/- √(24)
m = 4 +/- √(24) = 4 +/- 2√(6)
Then m, the slope of the line, may be 4 + 2√6 and 4 - 2√6
Answer:
Let start with what a polynomial is. Look in the step-by-step explanation.
Step-by-step explanation:
We know a polynomial has more than one term, right?
Answer:
the red one
Step-by-step explanation:
Answer:
2:1
Step-by-step explanation:
The perimeter of the first is twice as large as the 2nd
