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KiRa [710]
2 years ago
8

Sin(x+24) = Cos(y-x) ; Tan(z-24) - Tan(y-z)=0 find: Cos(y-z)

Mathematics
1 answer:
Delvig [45]2 years ago
4 0
<h3>Answer:</h3>

Cos(y-z) = Cos(z-24)

<h3>Step-by-step explanation:</h3>

You have two equations in three unknowns, so no solution for the unknowns is possible.

The tangent equation tells you ...

... tan(z -24) = tan(y -z)

... z -24 = y -z . . . . . . take the arctangent

... cos(y -z) = cos(z -24) . . . . take the cosine

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Step-by-step explanation:

Hi there!

We are given a right triangle (notice the 90°) angle, the measure of one of the acute angles as 60°, and the measure of the hypotenuse (the side OPPOSITE from the 90 degree angle) as 14

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The acute angles in a right triangle are complementary, meaning they add up to 90 degrees

Let's make the measure of the unknown acute angle x

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x=30°

So the measure of the other acute angle is 30 degrees

This makes the right triangle a special kind of right triangle, a 30°-60°-90°  triangle

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