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2 years ago

hayden bought 48 new trading cards three fourths of the new cards are baseball cards how many baseball cards did hayden buy

2 answers:

8 0

He bought 36 baseball cards. Since 3/4 of the 48 cards are baseball cards, you need to find 75% of 48, which is 75*48, which is 36 cards. Hope this helps.

lapo4ka [179]2 years ago

4 0

3/4 = 75

75% of 48 is?

.48 * 75 = 36

Answer: 36 cards are baseball cards

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What is the length of RU?

marta [7]

Answer:

Length of RU is 20 units.

Step-by-step explanation:

In ΔRSt and ΔRUT,

ST ≅ TU [Given]

RT ≅ RT [Reflexive property]

∠RTS ≅ ∠RTU [Both the angles are the right angles]

ΔRTS ≅ ΔRTU [By SAS property of congruence]

Therefore, RS ≅ RU [By CPCTC (corresponding parts of the congruent triangles are congruent]

8x = 6x + 5

8x - 6x = 5

2x = 5

x = 2.5

Length of RU = (6x + 5)

= 6(2.5) + 5

= 15 + 5

= 20

Length of RU is 20 units.

7 0

2 years ago

PLEASE HELP! Thanks!

rodikova [14]

Answer:

116

Step-by-step explanation:

For the rectangle 8×12 is 96.

For the triangle 8×5 is 40.

40/2 is 20.

96+20=116

8 0

2 years ago

How do I find the integral<br> ∫10(x−1)(x2+9)dxint10/((x-1)(x^2+9))dx ?

defon

$\int\frac{10}{(x-1)(x^2+9)}\ dx=(*)\\\\\frac{10}{(x-1)(x^2+9)}=\frac{A}{x-1}+\frac{Bx+C}{x^2+9}=\frac{A(x^2+9)+(Bx+C)(x-1)}{(x-1)(x^2+9)}\\\\=\frac{Ax^2+9A+Bx^2-Bx+Cx-C}{(x-1)(x^2+9)}=\frac{(A+B)x^2+(-B+C)x+(9A-C)}{(x-1)(x^2+9)}\\\Updownarrow\\10=(A+B)x^2+(-B+C)x+(9A-C)\\\Updownarrow\\A+B=0\ and\ -B+C=0\ and\ 9A-C=10\\A=-B\ and\ C=B\to9(-B)-B=10\to-10B=10\to B=-1\\A=-(-1)=1\ and\ C=-1$

$(*)=\int\left(\frac{1}{x-1}+\frac{-x-1}{x^2+9}\right)\ dx=\int\left(\frac{1}{x-1}-\frac{x+1}{x^2+9}\right)\ dx\\\\=\int\frac{1}{x-1}\ dx-\int\frac{x+1}{x^2+9}\ dx=\int\frac{1}{x-1}-\int\frac{x}{x^2+9}\ dx-\int\frac{1}{x^2+9}\ dx=(**)\\\\\#1\ \int\frac{1}{x-1}\ dx\Rightarrow\left|\begin{array}{ccc}x-1=t\\dx=dt\end{array}\right|\Rightarrow\int\frac{1}{t}\ dt=lnt+C_1=ln(x-1)+C_1$

$\#2\ \int\frac{x}{x^2+9}\ dx\Rightarrow \left|\begin{array}{ccc}x^2+9=u\\2x\ dx=du\\x\ dx=\frac{1}{2}\ du\end{array}\right|\Rightarrow\int\left(\frac{1}{2}\cdot\frac{1}{u}\right)\ du=\frac{1}{2}\int\frac{1}{u}\ du\\\\\\=\frac{1}{2}ln(u)+C_2=\frac{1}{2}ln(x^2+9)+C_2$

$\#3\ \int\frac{1}{x^2+9}\ dx=\int\frac{1}{x^2+3^2}\ dx=\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3\\\\therefore:\\\\\#1;\ \#2;\ \#3\Rightarrow(**)=ln(x-1)+C_1-\frac{1}{2}ln(x^2+9)+C_2-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3$

$\boxed{=ln(x-1)-\frac{1}{2}ln(x^2+9)-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C}$

4 0

3 years ago

A company estimates expenditures of $1.1 million in the first year, $1.4 million in the second year, $1.7 million in the third y

Temka [501]

In the data that are given above, it can be seen that the first point is $1.1 million, the second is $1.4 million which is 0.3 million greater than the first. Also, the third is $1.7 million which is $0.3 million greater than the third. The equation that best represents the given scenario is,
0.8 + 0.3(n)
The answer is the first choice.

5 0

2 years ago

What is the opposite of -(-82)?

labwork [276]

82 because it is the opposite of -(-82)

7 0

3 years ago

Read 2 more answers