i think so.
i learned this recently and my textbook says that neutrons and protons are in the nucleus and electrons orbit around the nucleus. :)
i hope i was able to help
Answer:
M₂ = 1.9 M
Explanation:
Given data;
Volume of sodium chloride = 200 mL
Molarity of sodium chloride = 4.98 M
Volume of water = 532 mL
Final Molarity = ?
Solution:
M₁V₁ = M₂V₂
M₂ = M₁V₁ /V₂
M₂ = 4.98 M × 200 mL / 532 mL
M₂ = 996 mL. M /532 mL
M₂ = 1.9 M
Answer:
ai) Rate law, ![Rate = k [CH_3 Cl] [Cl_2]^{0.5}](https://tex.z-dn.net/?f=Rate%20%3D%20k%20%5BCH_3%20Cl%5D%20%5BCl_2%5D%5E%7B0.5%7D)
aii) Rate constant, k = 1.25
b) Overall order of reaction = 1.5
Explanation:
Equation of Reaction:

If
, the rate of backward reaction is given by:
![Rate = k [A]^{a} [B]^{b}\\k = \frac{Rate}{ [A]^{a} [B]^{b}}\\k = \frac{Rate}{ [CH_3 Cl]^{a} [Cl_2]^{b}}](https://tex.z-dn.net/?f=Rate%20%3D%20k%20%5BA%5D%5E%7Ba%7D%20%5BB%5D%5E%7Bb%7D%5C%5Ck%20%3D%20%5Cfrac%7BRate%7D%7B%20%5BA%5D%5E%7Ba%7D%20%5BB%5D%5E%7Bb%7D%7D%5C%5Ck%20%3D%20%5Cfrac%7BRate%7D%7B%20%5BCH_3%20Cl%5D%5E%7Ba%7D%20%5BCl_2%5D%5E%7Bb%7D%7D)
k is constant for all the stages
Using the information provided in lines 1 and 2 of the table:
![0.014 / [0.05]^a [0.05]^b = 00.029/ [0.100]^a [0.05]^b\\0.014 / [0.05]^a [0.05]^b = 00.029/ [2*0.05]^a [0.05]^b\\0.014 / = 0.029/ 2^a\\2^a = 2.07\\a = 1](https://tex.z-dn.net/?f=0.014%20%2F%20%5B0.05%5D%5Ea%20%5B0.05%5D%5Eb%20%3D%2000.029%2F%20%5B0.100%5D%5Ea%20%5B0.05%5D%5Eb%5C%5C0.014%20%2F%20%5B0.05%5D%5Ea%20%5B0.05%5D%5Eb%20%3D%2000.029%2F%20%5B2%2A0.05%5D%5Ea%20%5B0.05%5D%5Eb%5C%5C0.014%20%2F%20%3D%200.029%2F%202%5Ea%5C%5C2%5Ea%20%3D%202.07%5C%5Ca%20%3D%201)
Using the information provided in lines 3 and 4 of the table and insering the value of a:
![0.041 / [0.100]^a [0.100]^b = 0.115 / [0.200]^a [0.200]^b\\0.041 / [0.100]^a [0.100]^b = 0.115 / [2 * 0.100]^a [2 * 0.100]^b\\](https://tex.z-dn.net/?f=0.041%20%2F%20%5B0.100%5D%5Ea%20%5B0.100%5D%5Eb%20%3D%200.115%20%2F%20%5B0.200%5D%5Ea%20%5B0.200%5D%5Eb%5C%5C0.041%20%2F%20%5B0.100%5D%5Ea%20%5B0.100%5D%5Eb%20%3D%200.115%20%2F%20%5B2%20%2A%200.100%5D%5Ea%20%5B2%20%2A%200.100%5D%5Eb%5C%5C)
![0.041 = 0.115 / [2 ]^a [2]^b\\ \[[2 ]^a [2]^b = 0.115/0.041\\ \[[2 ]^a [2]^b = 2.80\\\[[2 ]^1 [2]^b = 2.80\\\[[2]^b = 1.40\\b = \frac{ln 1.4}{ln 2} \\b = 0.5](https://tex.z-dn.net/?f=0.041%20%3D%200.115%20%2F%20%5B2%20%5D%5Ea%20%5B2%5D%5Eb%5C%5C%20%5C%5B%5B2%20%5D%5Ea%20%5B2%5D%5Eb%20%3D%200.115%2F0.041%5C%5C%20%5C%5B%5B2%20%5D%5Ea%20%5B2%5D%5Eb%20%3D%202.80%5C%5C%5C%5B%5B2%20%5D%5E1%20%5B2%5D%5Eb%20%3D%202.80%5C%5C%5C%5B%5B2%5D%5Eb%20%3D%201.40%5C%5Cb%20%3D%20%5Cfrac%7Bln%201.4%7D%7Bln%202%7D%20%5C%5Cb%20%3D%200.5)
The rate law is: ![Rate = k [CH_3 Cl] [Cl_2]^{0.5}](https://tex.z-dn.net/?f=Rate%20%3D%20k%20%5BCH_3%20Cl%5D%20%5BCl_2%5D%5E%7B0.5%7D)
The rate constant
then becomes:
![k = 0.014 / ( [0.050] [0.050]^(0.5) )\\k = 1.25](https://tex.z-dn.net/?f=k%20%3D%200.014%20%2F%20%28%20%5B0.050%5D%20%5B0.050%5D%5E%280.5%29%20%29%5C%5Ck%20%3D%201.25)
b) Overall order of reaction = a + b
Overall order of reaction = 1 + 0.5
Overall order of reaction = 1.5
Answer:
yes
Explanation:
How many grams of KCl will dissolve in 1 liter of H2O at 50 °C? 5. 58.0 g of K2Cr2O7 is added to 100 g H2O at. 0 °C. With constant stirring, to what temp-.
Enzymes catalyze the chemical reactions, they act upon the reaction substrates and speed up the reaction. Enzymes have active sites, the places where the reaction substrates interact with the enzyme bringing about the conversion of substrates to products. So, as the enzyme concentration increases the rate of reaction increases till a point where the rate is leveled off. The rate does not further increase, as the substrate might have become limiting at that point. All the available amount of substrate would have been associated with the active sites of the enzymes. So, at that point although there is enough catalyst, lack of substrate would limit the rate of reaction.