3 years ago

How does the rider’s ability to stop the bike change as the bike moves down a steep hill

1 answer:

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If you break while going down hill you become front heavy and will flip forward due to the change of gravity because of the downward slope of the hill

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Use the Periodic Table of the Elements to answer

Juliette [100K]

Answer:

b. lithium

Explanation:

Li the least likely, to lose an electron.

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3 years ago

The fact that HBO2, a reactive compound, was produced rather than the relatively inert B2O3 was a factor in the discontinuation

Reil [10]

Answer:

1027.62 g

Explanation:

For $B_2H_6$ :-

Mass of $B_2H_6$ = 296.1 g

Molar mass of $B_2H_6$ = 27.66 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{296.1\ g}{27.66\ g/mol}$

$Moles\ of\ B_2H_6= 10.705\ mol$

From the balanced reaction:-

$B_2H_6(g) + 3 O2_{(l)}\rightarrow 2 HBO_2_{(g)}+ 2 H_2O_{(l)}$

1 mole of $B_2H_6$ react with 3 moles of oxygen

Thus,

10.705 mole of $B_2H_6$ react with 3*10.705 moles of oxygen

Moles of oxygen = 32.115 moles

Molar mass of oxygen gas = 31.998 g/mol

<u>Mass = Moles * Molar mass = 32.115 * 31.998 g = 1027.62 g</u>

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3 years ago

How many grams of sucrose (c12h22o11) are in 1.55 l of 0.758 m sucrose solution? express your answer in grams to three significa

satela [25.4K]

The molecular formula of sucrose is - C₁₂H₂₂O₁₁
molecular mass of sucrose - 342 g/mol
molarity of sucrose solution is 0.758 M
In 1 L solution the number of sucrose moles are - 0.758 mol
Therefore in 1.55 L solution, sucrose moles are - 0.758 mol/L x 1.55 L
= 1.17 mol
The mass of 1.17 mol of sucrose is - 1.17 mol x 342 g/mol = 4.00 x 10² g

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2 years ago

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Which statement is true for nuclear reactions but not for chemical reactions?

IrinaVladis [17]

Answer:maybe C

Explanation:

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the boiling points of two liquids are 120°C and 240°C, to what minimum temperature do I have to heat them in order to separate t

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