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3 years ago

Determine if the following compounds will be soluble or insoluble in water?

Chemistry

1 answer:

Molodets [167]3 years ago

7 0

Answer:

a) Insoluble

b) Soluble

c) Insoluble

d) Insoluble

e) Soluble

f) Soluble

Explanation:

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What volume of a 3.50 M Na3PO4 solution would you use to make 1.50 L of a 2.55 M Na3PO4 solution?

kati45 [8]

The answer is A. 1.09 L

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2 years ago

Salicylic acid (C7H6O3) reacts with acetic anhydride (C4H6O3) to form acetylsalicylic acid (C9H8O4).

zavuch27 [327]

Answer : The correct option is, (B) Salicylic acid

Solution :

First we have to calculate the moles of salicylic acid and acetic anhydride.

$\text{Moles of }C_7H_6O_3=\frac{\text{Mass of }C_7H_6O_3}{\text{Molar mass of }C_7H_6O_3}=\frac{70g}{138.121g/mole}=0.507moles$

$\text{Moles of }C_4H_6O_3=\frac{\text{Mass of }C_4H_6O_3}{\text{Molar mass of }C_4H_6O_3}=\frac{80g}{102.09g/mole}=0.783moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2C_7H_6O_3(aq)+C_4H_6O_3(aq)\rightarrow 2C_9H_8O_4(aq)+H_2O(l)$

From the balanced reaction we conclude that

As, 2 moles of salicylic acid react with 1 mole of acetic anhydride

So, 0.507 moles of salicylic acid react with $\frac{0.507}{2}=0.2535$ mole of acetic anhydride

The excess of acetic anhydride = 0.783 - 0.2535 = 0.5295 moles

That means the in the given balanced reaction, salicylic acid is a limiting reagent because it limits the formation of products and acetic anhydride is an excess reagent.

Hence, the limiting reagent is, salicylic acid.

7 0

3 years ago

Which energy source has been developed and improved by chemists?

Nostrana [21]

Nuclear hope this helps

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3 years ago

Read 2 more answers

ammonium bromide reacts with copper(i) sulfate in aqueous solution to form a solid precipitate. what is the net ionic equation f

sukhopar [10]

Answer:

$Br^-(aq)+Cu^+(aq)\rightarrow CuBr(s)$

Explanation:

Hello,

In this case, the molecular chemical reaction is written as:

$2NH_4Br(aq)+Cu_2S(aq)\rightarrow 2CuBr(s)+(NH_4)_2SO_4(aq)$

In such a way, considering the net ionic notation and the solid yielded copper (I) bromide, we write:

$2NH_4^+(aq)+Br^-(aq)+Cu^+(aq)+SO_4^{2-}(aq)\rightarrow CuBr(s)+NH_4^+(aq)+SO_4^{2-}(aq)$

Whereas ammonium and sulfate ions are spectator ions, therefore the net ionic equation is:

$Br^-(aq)+Cu^+(aq)\rightarrow CuBr(s)$

Regards.

5 0

3 years ago

Define oxidation, reduction, and oxidation number. Describe how oxidation and reduction affect the oxidation number of an elemen

Andreas93 [3]

Answer:

Oxidation: the loss of electrons

Reduction: the gain of electrons

Oxidation number: the charge based on the number of electrons assigned to an atom as compared to the neutral atom

Explanation:

The oxidation number of a neutral atom is zero. When the atom is oxidized, it loses electrons (which have a negative charge), so the oxidation number goes up. When the atom is reduced, it gains electron (it gains negative charge), so the oxidation number goes down.

3 0

3 years ago