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2 years ago

6

A certain juggler usually tosses balls vertically to a height 3.8 yd. To what height must they be tossed if they are to spend tw

ice as much time in the air?

1 answer:

Maksim231197 [3]2 years ago

3 0

Answer:

15.2 yards

Step-by-step explanation:

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From a height of 50 meters above sea level on a cliff, two ships are sighted due west. The angles of depression are 61° and 28°.

Olenka [21]

Answer:

The ships are 66 meters apart.

Step-by-step explanation:

For the sake of convenience, let us label ships A and B

As shown in the figure, the distances to the ships from right triangles.

The distance to the ship A is $d_1$ and it is given by

$tan (61^o)= \dfrac{50}{d_1}$

$d_1=\dfrac{50}{tan (61^o)}$

$\boxed{d_1= 27.71m}$

And the distance to the ship B is $d_2$ and is given by

$tan (28^o)= \dfrac{50}{d_2}$

$d_2=\dfrac{50}{tan (28^o)}$

$\boxed{ d_2=94.04m}$

Therefore, the distance $d$ between the ships A and B is

$d= d_2-d_1=94.04-27.7\\\\\boxed{d=66m}$

In other words, the ships are 66 meters apart.

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2 years ago

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bixtya [17]

Answer:

1. 3*8*10=240

2.6*6*12=432

Step-by-step explanation:

Hope that helps

Use l*w*h

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2 years ago

Ab (3a-5b) equals to?

Aleks04 [339]

Answer:

3a^2b-5ab^2

Step-by-step explanation:

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2 years ago

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Which equation is represented by the table?

lys-0071 [83]

What table? i think you need to upload a picture of it or something

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2 years ago

1.2 repeating as a fraction

Step2247 [10]

11/9 is what im thinking

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2 years ago