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4 years ago

11

How do you distribute to solve the equation 28-2(4^2*4)?

1 answer:

astra-53 [7]4 years ago

5 0

Answer:

28-2(4^2*4)

28 - 2 (4*4*4)

28-2(64)

28 -128 = 100

Step-by-step explanation:

28-2(4^2*4)

28 - 2 (4*4*4)

28-2(64)

28 -128 = 100

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grandymaker [24]

Answer: 14,658,134,400

<u>Step-by-step explanation:</u>

There are 52 numbers to start with. After choosing the first number, there are 51 numbers remaining, etc.

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You can also find the answer using the following formula:

$\dfrac{52!}{(52-6)!}=\dfrac{52!}{46!}=\dfrac{52\times 51\times 50\times 49\times 48\times 47 \times 46!}{46!}\\\\\\.\qquad \qquad \qquad \quad = 52\times 51\times 50\times 49\times 48\times 47\\ \\\\.\qquad \qquad \qquad \quad =\large\boxed{14,658,134,400}$

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3 years ago

Help pls <br> 5/2x-7=3/4x+14

katrin2010 [14]

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10x−28=3x+56

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4 years ago

(3,-5),(3,-2),(3,5),(3,8) find the slope.

crimeas [40]

Answer:

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Step-by-step explanation:

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3 years ago