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Helen [10]
3 years ago
11

How do you distribute to solve the equation 28-2(4^2*4)?

Mathematics
1 answer:
astra-53 [7]3 years ago
5 0

Answer:

28-2(4^2*4)

28 - 2 (4*4*4)

28-2(64)

28 -128 = 100

Step-by-step explanation:

28-2(4^2*4)

28 - 2 (4*4*4)

28-2(64)

28 -128 = 100

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For every 3 packages, she uses 1/2 a roll of wrapping paper

if she uses 2 1/2 rolls.....

(2 1/2) / (1/2) ....* 3
(5/2) / (1/2).....* 3
(5/2 * 2) * 3
5 * 3 =
15 packages <===
7 0
3 years ago
PLZZZ ANSWER QUICK!!!
GREYUIT [131]

Answer:

A. x - 38.45 = 17.71

Step-by-step explanation:

The price of the shirt subtracted off the amount of money she had before would give 17.71

7 0
3 years ago
The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in t
EleoNora [17]
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t

h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79

g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8

Between 2 and 3 seconds. 
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1

h(t) = g(t) ⇒ 131 = 131

<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
5 0
3 years ago
In math class a student scored 82 85 92 93 on 4 math test respectively what must the student score on a 5 test to earn an averag
prisoha [69]
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3 years ago
Math escape room maze ( I need help) I know it goes A,E,I but I don’t know what goes next)
miskamm [114]

Answer:

9

Step-by-step explanation:

Use angle summation:

∠HGE + ∠EGF = ∠HGF

3x + 11 + 110 = 16x + 4

117 = 13x

x = 9

4 0
3 years ago
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