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Tomtit [17]
2 years ago
7

Solve this with your work shown. (50 POINTS.)​

Mathematics
1 answer:
Ket [755]2 years ago
7 0

top problems:

1-) x²-2x-8

<h2>(x-4)(x+2)</h2>

---------------------

2-) 4s²-4s+1

<h2>(2s-1)²</h2>

---------------------

3-) 6x²-3-7x

<h2>(2x-3)(3x+1)</h2>

---------------------

4-) 4u²+8u

<h2>4u(u+2)</h2>

---------------------

5-) t²-15

<h2>2t</h2>

---------------------

6-) 3x²-x-4

<h2>(3x-4)(x+1)</h2>

bottom problems:

1-) \frac{1}{4},-1

y=x²+\frac{3x}{4}-\frac{1}{4}

---------------------

2-)\sqrt{2},\frac{1}{3}

<h2>y=x²-\frac{x}{3}-\sqrt{2}x+\frac{\sqrt{2} }{3}</h2>

---------------------

3-) 0, √5

<h2>y=x²-x√5</h2>

---------------------

4-) 1,1

<h2>y= x²-2x+1</h2>

---------------------

5-)-\frac{1}{4}, \frac{1}{4}

<h2>y=x²-\frac{1}{16}</h2>

---------------------

6-) 4,1

<h2>y=x²-5x+4</h2>

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Help please ! Please
gizmo_the_mogwai [7]

Answer:

15, 8, 25 The teacher payed 0.40 per book.

Step-by-step explanation:

4/10 = 2/5 Simplify the 4/10 to find the unit rate.

15: 2/5 = 6/x Set up your proportion.

    2x   =30 Cross multiply

    /2      /2 Divide both sides by 2 to isolate x

     x     =15

8: 2/5 = x/20 Set up proportion

   40  =5x Cross multiply

    /5     /5 Divide both sides by 5 to isolate x

     8  =x

25: 2/5 = 10/x Set up proportion

      2x  =50 Cross multiply

       /2     /2 Divide both sides by 2 to isolate x

        x   =25

Graph: y=mx+b To graph, you will need to use y=mx+b format

           y= 2/5 x+2 2/5 is your unit rate. Your rate changes every 2 books bought. To graph, start at (0,2) and go up 2 and to the right 5, plot. Continue moving up 2 and to the right 5 to graph.

The teacher payed 0.40 per book because 2/5 simplifies to 0.40.

   

8 0
3 years ago
14% of 980?
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3 years ago
Please help me find the answer​
Ksivusya [100]

Answer:

-4 1/4

Step-by-step explanation:

-7 3/4 + 3 1/2 = -4 1/4

8 0
3 years ago
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
Regina left the coffee shop traveling 9 mph. Then, 3 hours later, Janai left traveling the same direction at
damaskus [11]

Answer:

<em>suwi6q74diyer7ityw7reuDjuss36audlsgo74wridoyaurslhjsgjfaufalakateUd</em>

Step-by-step explanation:

will3urafg-"7'-"/-()4<u> </u><u>mhl374</u><u>y</u><u>3</u><u>l</u><u>u</u><u>s</u><u>d</u><u>u</u><u>s</u><u>i</u><u>t</u><u>z</u><u>l</u><u>a</u><u>7</u><u>w</u><u>h</u><u>f</u><u>z</u><u>s</u><u>p</u><u>r</u><u>X</u><u>j</u><u>a</u><u>u</u><u>e</u><u>g</u><u>k</u><u>z</u><u>h</u><u>r</u><u>o</u><u>y</u>

5 0
2 years ago
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