3a. The graph shows a school's profit P for selling x lunches on one day. PART A: What is the school's profit for selling 120 lu
2 answers:
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<h2><u>Requi</u><u>red</u><u> Answer</u><u> </u><u>:</u><u>-</u></h2>
Given system of linear equations are ,
- x + y = 2
- -3x + y = 2
And we need to find the Solution of the linear equation . So let's Firstly number the equations .
<u>→</u><u> </u><u>Multipl</u><u>ying</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>by</u><u> </u><u>3</u><u> </u><u>,</u>
=> 3 ( x + y ) = 2*3
=> 3x + 3y = 6
<u>→</u><u> </u><u>Addin</u><u>g</u><u> </u><u>the</u><u> </u><u>two</u><u> </u><u>equations </u><u>,</u><u> </u>
=> 3x + 3y -3y + y = 6 + 2
=> 4y = 8
=> y = 8/4
=> y = 2
<u>→</u><u> </u><u>Put</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>in</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>,</u>
=> x + y = 2
=> x + 2 = 2
=> x = 2- 2
=> x = 0
<h3><u>★</u><u> </u><u>Hence</u><u> the required solution is ( 0 , 2 ) .</u></h3>