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nikitadnepr [17]
3 years ago
7

When the blood flows through the capillary bed, most of the plasma will return to the heart through the venules. What happens to

the plasma that does not travel to the venules? It is removed by the lymphatic vessels. It is lost as heat. It returns to the arterioles. It stays in the capillary bed.
Physics
2 answers:
Bas_tet [7]3 years ago
8 0
The answer is the 2nd sentence.
Vlad [161]3 years ago
3 0

The correct answer is option A , It is removed by the lymphatic vessels

There is loss of watery plasma in the body that creates a hyperosmotic solution within the capillaries and venules. This loss causes the blood plasma (nearly 85%) to move in backward direction into the capillaries near the venules . The remaining 15% blood plasma, move out into the lymphatic vessel through the interstitial fluid. This lymphatic fluid is similar in composition to the interstitial fluid and passes through lymph nodes before it returns to the heart via the vena cava.

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____ is undeniably accepted by scientists all over the world as the primary language of science.
faust18 [17]

Answer:

Latin

Explanation:

In order for the scientists to have a common and official name for a particular thing that can be understood by every scientist in the world, a single language has been established for the purpose. The language chosen is the Latin language. The official scientific names are given in this language, so it is a necessity for the scientists to know and understand this language. The terms that are commonly used are regional, and they come in many different languages, which is why this language has been chosen. Occasionally, the ancient Greek language is used as well, though much less than the Latin.

6 0
3 years ago
Read 2 more answers
As outlaws escape in their getaway ear, which goes 3/4 c, the police officer fires a bullet from a pursuit ear, which only goes
Mariulka [41]

Answer:

a) Bullet will hit

b) Bullets will not hit

Explanation:

Given:

The velocity of the bullet, u = \frac{1}{3}c in the rest frame of the bullet pursuit car

The velocity of the original frame of reference, v = -\frac{1}{2}c with respect to the pursuit car.

Now, according to the Galileo

the velocity of the bullet in the original frame of reference (u') will be

u' = u - v

on substituting the values we get

u' = \frac{1}{3}c-(-\frac{1}{2}c)

or

u' = \frac{1}{3}c+\frac{1}{2}c

or

u' = \frac{5}{6}c

since this velocity ( \frac{5}{6}c) is greater than the ( \frac{3}{4}c)

hence,

<u>the bullet will hit</u>

Now, according to the Einstein theory

the velocity of the bullet in the original frame of reference (u') will be

u'=\frac{u-v}{1-\frac{uv}{c^2}}

on substituting the values we get

u'=\frac{\frac{1}{3}c-\frac{1}{2}c}{1-\frac{\frac{1}{3}c\times \frac{1}{2}c}{c^2}}

or

u'=\frac{\frac{5}{6}c}{1-\frac{1}{6}}

or

u'=\frac{5}{7}c

since,

u'=\frac{5}{7}c is less than  ( \frac{3}{4}c), this means that the bullet will not hit

7 0
3 years ago
A man is pulling on a rope with a force of 63 N directed at an angle of 61◦ to the horizontal. What is the y-component of this f
Sergio039 [100]
Y = 63sin61

y = 55.1 N
6 0
3 years ago
A loop of wire is at the edge of a region of space containing a uniform magnetic field B. The plane of the loop is perpendicular
il63 [147K]

Answer:

The question is not clear enough. So i have attached a copy of the correct question.

A) B = V/c

B) c = Lv

Explanation:

A) we know that formula for magnetic flux is;

Φ = BA

Where B is magnetic field and A is area

Now,

Let's differentiate with B being a constant;

dΦ/dt = B•dA/dt

From faradays law, the EMF induced is given as;

E = -dΦ/dt

However, we want to express it in terms of V and E.M.F is also known as potential difference or Voltage.

Thus, V = -dΦ/dt

Thus, we can now say that;

-V = B•dA/dt

Now from the question, we are told that dA/dt = - c

Thus;

-V = B•-c

So, V = Bc

Thus, B = V/c

B) according to Faraday's Law or Lorentz Force Law, an electromotive force, emf, will be induced between the two ends of the sidelength:

Thus;

E =LvB or can be written as; V = LvB

Where;

V is EMF

L is length of bar

v is velocity

From the first solution, we saw that;

V = Bc

Thus, equating both of the equations, we have;

Bc = LvB

B will cancel out to give;

c = Lv

Explanation:

8 0
3 years ago
When a 0.292 kg mass on a string is swung at 8.45 m/s, it feels a centripetal acceleration of 78.9 m/s^2. What is the radius of
miss Akunina [59]

Answer:

r=0.26m

Explanation:

F=mv^2/r

78.9=0.292*(8.45)^2/r

r=0.292*(8.45)^2/78.9

r=0.26m

3 0
3 years ago
Read 2 more answers
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