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nikitadnepr [17]
3 years ago
7

When the blood flows through the capillary bed, most of the plasma will return to the heart through the venules. What happens to

the plasma that does not travel to the venules? It is removed by the lymphatic vessels. It is lost as heat. It returns to the arterioles. It stays in the capillary bed.
Physics
2 answers:
Bas_tet [7]3 years ago
8 0
The answer is the 2nd sentence.
Vlad [161]3 years ago
3 0

The correct answer is option A , It is removed by the lymphatic vessels

There is loss of watery plasma in the body that creates a hyperosmotic solution within the capillaries and venules. This loss causes the blood plasma (nearly 85%) to move in backward direction into the capillaries near the venules . The remaining 15% blood plasma, move out into the lymphatic vessel through the interstitial fluid. This lymphatic fluid is similar in composition to the interstitial fluid and passes through lymph nodes before it returns to the heart via the vena cava.

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When magnesium fluoride reacts with iodine, the products are fluorine and magnesium iodide. What would the equation be?
likoan [24]

Answer:

Explanation:

Every chemical reaction can be represented by simple chemical equations that shows how compounds are combining to give some products.

Such reactions are usually made up of:

     Reactants on the left hand side

     Products on the right hand side

            Reactants  →  Products

In this given problem;

            Reactants are :   Magnesium fluoride  = MgF₂

                                             Iodine in form of Iodide   = I₂

           Product : Magnesium iodide  = MgI₂

             

               MgF₂   +     I₂    →       MgI₂   +   F₂

   

                             

   

7 0
3 years ago
A stone is dropped from a cliff and falls 9.44 meters. What is the speed of the stone when it reaches the ground?
Lunna [17]

Answer:

option A

Explanation:

given,                                              

height of the drop of stone = 9.44 m

speed of the stone = ?                          

As the stone is dropped the energy of the stone will be conserved.

using conservation of energy.            

Potential energy = Kinetic energy    

m g h = \dfrac{1}{2} m v^2  

     v = \sqrt{2gh}                  

     v = \sqrt{2\times 9.8 \times 9.44}

     v = \sqrt{185.024}              

            v = 13.60 m/s                      

Hence, the correct answer is option A

3 0
3 years ago
A bicycle tire has a pressure of 7.00×105 N/m2 at a temperature of 18.0ºC and contains 2.00 L of gas. What will its pressure be
stepan [7]

Answer:

p_2 = 664081 N/m^{2}

Explanation:

from the ideal gas law we have

PV = mRT

P = \rho RT

\rho = \frac{P}{RT}

HERE  R is gas constant for dry air  =  287  J K^{-1} kg^{-1}

\rho = \frac{7.00 10^{5}}{287(18+273)}

\rho = 8.38 kg/m^{3}

We know by ideal gas law

\rho = \frac{m_1}{V_1}

m_1 = \rho V_1 = 8.38 *2*10^{-3}

m_1 = 0.0167 kg

for m_2

m_2 = \rho V_i - V_removed

m_2 = 8.38*(.002 - 10^{-4})

m_2 = 0.0159 kg

WE KNOW

PV = mRT

V, R and T are constant therefore we have

P is directly proportional to mass

\frac{p_2}{p_1}=\frac{m_2}{m_1}

p_2 = p_1 * \frac{m_2}{m_1}

p_2 =7*10^{5} * \frac {.0159}{0.0167}

p_2 = 664081 N/m^{2}

8 0
2 years ago
A student is getting ready to go on a bike ride, but her bike back tire is flat! She connects a pump to the valve and adds air t
Mariana [72]
Wheres the answer below?
4 0
2 years ago
A thin hoop is hung on a wall, supported by a horizontal nail. The hoop's mass is M=2.0 kg and its radius is R=0.6 m. What is th
boyakko [2]

Answer:

Explanation:

Given that,

Mass of the thin hoop

M = 2kg

Radius of the hoop

R = 0.6m

Moment of inertial of a hoop is

I = MR²

I = 2 × 0.6²

I = 0.72 kgm²

Period of a physical pendulum of small amplitude is given by

T = 2π √(I / Mgd)

Where,

T is the period in seconds

I is the moment of inertia in kgm²

I = 0.72 kgm²

M is the mass of the hoop

M = 2kg

g is the acceleration due to gravity

g = 9.8m/s²

d is the distance from rotational axis to center of of gravity

Therefore, d = r = 0.6m

Then, applying the formula

T = 2π √ (I / MgR)

T = 2π √ (0.72 / (2 × 9.8× 0.6)

T = 2π √ ( 0.72 / 11.76)

T = 2π √0.06122

T = 2π × 0.2474

T = 1.5547 seconds

T ≈ 1.55 seconds to 2d•p

Then, the period of oscillation is 1.55seconds

6 0
2 years ago
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