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s344n2d4d5 [400]
3 years ago
15

What's the answer for question 2?

Physics
1 answer:
Luden [163]3 years ago
8 0
Sway bar ??? Idk if that's right
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This isn’t homework related but what methods do you guys recommend for shifting realities ? .I’ve tried the raven method for wee
elena55 [62]

Answer:

subs

Explanation:

I've seen subliminals online that are supposed to help shifting. You could see for yourself if they work for you. You could probably also use the method where you act like you already have your desires and results. I have seen a lot of people act as if they have their desires and affirm it constantly. Ex: you want to lose weight, so you act as if you already are your desired weight and tell yourself that you are such and such weight, and don't contradict it by saying that you aren't. I hope that this helps.

6 0
3 years ago
Before the experiment, the total momentum of the system is 2.5 kg m/s to the right and the kinetic energy is 5J. After the exper
finlep [7]

Answer:

Option (b) is correct.

Explanation:

Elastic collision is defined as a collision where the kinetic energy of the system remains same. Both linear momentum and kinetic energy are conserved in case of an elastic collision.

Inelastic collision is defined as a collision where kinetic energy of the system is not conserved whereas the linear momentum is conserved. This loss of kinetic energy may due to the conversion to thermal energy or sound energy or may be due to the deformation of the materials colliding with each other.

As given in the problem, before the collision, total momentum of the system is 2.5~Kg~m~s^{-1} and the kinetic energy is 5~J. After the collision, the total momentum of the system is  2.5~Kg~m~s^{-1}, but the kinetic energy is reduced to 4~J. So some amount of kinetic energy is lost during the collision.

Therefor the situation describes an inelastic collision (and it could NOT be elastic).

5 0
3 years ago
a rocket, initially at rest, steadily gains speed at a rate of 13.0m/s^2 for 6.40 during take-off. How far did the rocket travel
Aliun [14]

Explanation:

sbsbbsbshdi she sgebsbwhwjge hsshhdhsshshsuus she's used ydhdyuyddhdhdy hehehe due susshsuhdhdhd ffujfufudhdndndjd d

3 0
3 years ago
It takes a minimum distance of 76.50 m to stop a car moving at 15.0 m/s by applying the brakes (without locking the wheels). Ass
Vinvika [58]

The minimum stopping distance when the car is moving at 32.0 m/s is 348.3 m.

<h3>Acceleration of the car </h3>

The acceleration of the car before stopping at the given distance is calculated as follows;

v² = u² + 2as

when the car stops, v = 0

0 = u² + 2as

0 = 15² + 2(76.5)a

0 = 225 + 153a

-a = 225/153

a = - 1.47 m/s²

<h3>Distance traveled when the speed is 32 m/s</h3>

If the same force is applied, then acceleration is constant.

v² = u² + 2as

0 = 32² + 2(-1.47)s

2.94s = 1024

s = 348.3 m

Learn more about distance here: brainly.com/question/4931057

#SPJ1

5 0
2 years ago
Anyone know a GOOD show on Netflix please kid shows pleaseeeee
Afina-wow [57]

Answer:

like horror? or action haha

Explanation:

7 0
3 years ago
Read 2 more answers
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